main()
{
char *p = “ayqm”;
char c;
c = ++*p++;
printf(“%c”,c);
}
Answer / susie
Answer :
b
Explanation:
There is no difference between the expression ++*(p++) and
++*p++. Parenthesis just works as a visual clue for the
reader to see which expression is first evaluated.
| Is This Answer Correct ? | 5 Yes | 1 No |
What is the output of the program given below main() { signed char i=0; for(;i>=0;i++) ; printf("%d\n",i); }
main() { int c[ ]={2.8,3.4,4,6.7,5}; int j,*p=c,*q=c; for(j=0;j<5;j++) { printf(" %d ",*c); ++q; } for(j=0;j<5;j++){ printf(" %d ",*p); ++p; } }
Program to Delete an element from a doubly linked list.
4 Answers College School Exams Tests, Infosys,
union u { struct st { int i : 4; int j : 4; int k : 4; int l; }st; int i; }u; main() { u.i = 100; printf("%d, %d, %d",u.i, u.st.i, u.st.l); } a. 4, 4, 0 b. 0, 0, 0 c. 100, 4, 0 d. 40, 4, 0
main() { unsigned char i=0; for(;i>=0;i++) ; printf("%d\n",i); }
struct Foo { char *pName; char *pAddress; }; main() { struct Foo *obj = malloc(sizeof(struct Foo)); clrscr(); obj->pName = malloc(100); obj->pAddress = malloc(100); strcpy(obj->pName,"Your Name"); strcpy(obj->pAddress, "Your Address"); free(obj); printf("%s", obj->pName); printf("%s", obj->pAddress); } a. Your Name, Your Address b. Your Address, Your Address c. Your Name Your Name d. None of the above
x=2 y=3 z=2 x++ + y++; printf("%d%d" x,y);
How to read a directory in a C program?
#include<stdio.h> main() { int a[2][2][2] = { {10,2,3,4}, {5,6,7,8} }; int *p,*q; p=&a[2][2][2]; *q=***a; printf("%d..%d",*p,*q); }
#ifdef something int some=0; #endif main() { int thing = 0; printf("%d %d\n", some ,thing); }
main() { int i, j; scanf("%d %d"+scanf("%d %d", &i, &j)); printf("%d %d", i, j); } a. Runtime error. b. 0, 0 c. Compile error d. the first two values entered by the user
main(int argc, char **argv) { printf("enter the character"); getchar(); sum(argv[1],argv[2]); } sum(num1,num2) int num1,num2; { return num1+num2; }