Answer / pragathi

void main()
{
if(printf("campus force training"))
{
}
}

Answer / pragathi

main()
{
if(printf("campus force training"))
break;
}

Answer / bhavin

void main()
{
if(printf(" Campus force training")
{}
getch();
}

Write a complete program that consists of a function that can receive two numbers from a user (M and N) as a parameter. Then print all the numbers between the two numbers including the number itself. If the value of M is smaller than N, print the numbers in ascending flow. If the value of M is bigger than N, print the numbers in descending flow. may i know how the coding look like?

2 Answers  

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write a origram swaoing valu without 3rd variable

2 Answers  

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¦void main() ¦{ ¦int i=10,j; ¦ j=i+++i+++i; ¦printf("%d",j); ¦getch(); ¦} ¦ output:-30 but in same question if we write as- ¦void main() ¦{ ¦int i=10; ¦ int j=i+++i+++i; ¦printf("%d",j); ¦getch(); ¦} ¦ output:-33 why output is changed from 30 to 33. Can any body answer...

3 Answers  

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write a c program to print magic square of order n when n>3 and n is odd?

1 Answers   HCL,

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main() { static int a[3][3]={1,2,3,4,5,6,7,8,9}; int i,j; static *p[]={a,a+1,a+2}; for(i=0;i<3;i++) { for(j=0;j<3;j++) printf("%d\t%d\t%d\t%d\n",*(*(p+i)+j), *(*(j+p)+i),*(*(i+p)+j),*(*(p+j)+i)); } }

1 Answers  

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main() { int i = 3; for (;i++=0;) printf(“%d”,i); }

1 Answers   CSC,

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Is the following statement a declaration/definition. Find what does it mean? int (*x)[10];

1 Answers  

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main() { char s[ ]="man"; int i; for(i=0;s[ i ];i++) printf("\n%c%c%c%c",s[ i ],*(s+i),*(i+s),i[s]); }

1 Answers   DCE,

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Write a routine to draw a circle (x ** 2 + y ** 2 = r ** 2) without making use of any floating point computations at all.

2 Answers   Mentor Graphics, Microsoft,

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main() { char * strA; char * strB = I am OK; memcpy( strA, strB, 6); } a. Runtime error. b. I am OK c. Compile error d. I am O

4 Answers   HCL,

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main() { char c=' ',x,convert(z); getc(c); if((c>='a') && (c<='z')) x=convert(c); printf("%c",x); } convert(z) { return z-32; }

1 Answers  

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main(int argc, char **argv) { printf("enter the character"); getchar(); sum(argv[1],argv[2]); } sum(num1,num2) int num1,num2; { return num1+num2; }

1 Answers  

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