Answer / sameer

it because arrays index are pointers and you are giving
offsets from the base pointer & base pointer is starting
element address so it has offset zero from base pointer

Answer / surya.raj

Since I found this questions answer on a another website and
I can do copy and paste from there, but in order to make
copyright and royalty of original poster I am not tending to
do that so, here is the link below from where you can get
answer of your question.

http://developeronline.blogspot.com/2008/04/why-array-index-should-start-from-0.html

int i=10; main() { extern int i; { int i=20; { const volatile unsigned i=30; printf("%d",i); } printf("%d",i); } printf("%d",i); }

1 Answers  

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¦void main() ¦{ ¦int i=10,j; ¦ j=i+++i+++i; ¦printf("%d",j); ¦getch(); ¦} ¦ output:-30 but in same question if we write as- ¦void main() ¦{ ¦int i=10; ¦ int j=i+++i+++i; ¦printf("%d",j); ¦getch(); ¦} ¦ output:-33 why output is changed from 30 to 33. Can any body answer...

3 Answers  

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main() { int i=5; printf("%d%d%d%d%d%d",i++,i--,++i,--i,i); }

7 Answers  

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How we will connect multiple client ? (without using fork,thread)

3 Answers   TelDNA,

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how to return a multiple value from a function?

5 Answers   Wipro,

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main() { char *p = “ayqm”; printf(“%c”,++*(p++)); }

29 Answers   IBM, TCS, UGC NET, Wipro,

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What is the output for the program given below typedef enum errorType{warning, error, exception,}error; main() { error g1; g1=1; printf("%d",g1); }

1 Answers  

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main() { int i; clrscr(); printf("%d", &i)+1; scanf("%d", i)-1; } a. Runtime error. b. Runtime error. Access violation. c. Compile error. Illegal syntax d. None of the above

1 Answers   HCL,

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main() { printf("\nab"); printf("\bsi"); printf("\rha"); }

3 Answers  

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void main() { int i; char a[]="\0"; if(printf("%s\n",a)) printf("Ok here \n"); else printf("Forget it\n"); }

3 Answers   Accenture,

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what is variable length argument list?

2 Answers  

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#include <stdio.h> int main(void) { int a=4, b=2; a=b<<a+b>>2 ; printf("%d",a); return 0; }

0 Answers   Student,

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