Answer / abhishek joshi ( h7 )

all these methods are too long.....


HAVE A LOOK ON SIMPLEST AND THE SHORTEST OF ALL
IN JUST ONE LINE YOU CAN REVERSE ANY STRING
and yes..... without using string.h

CODE IS :



#include<stdio.h>
main()
{
int l,i,j; /*declaring integer variables*/
char str[10],temp[10]; /* declaring string variables*/

/* Now taking input from the user*/

printf("\n enter any string to reverse =>");
scanf("%s",&str); /* passing into the variable*/

/*finding the lenth of the entered string */
for (l=0;str[l];++l); /*length found;amazing code!isnt it?*/
{printf("\nThis is the length of the string =>%d\n",l);}

/*making loop for reversing the given string*/

j=l;
for (i=0;j>=0;i++,j--)
{
temp[i]=str[j]; /* Note that the string is reversed */
/* and saved into new variable i.e temp*/
}

/*Now printing the reversed string*/
printf("\n this is the reversed string =>");

for (i=0;i<=l;i++)
{printf("%c",temp[i]);

/* this loop is calling the characters from the temp variable*/
}
}
/*End of program :-D*/




So this was my coding .....
am abhishek joshi.....
computer and network engineer....
am dot net programmer but also have indepth knowledge of C
and C++
and if you feel this code helpful then at least mention one
thanks vote on my mail id : h7_2007@yahoo.co.in

also if you want such amazing codes of dot net then u can
contact me.....
+919907428052
:-D have a great day.....

Answer / raghuram.a

#include<iostream.h>
#include<conio.h>
#include<string.h>
#include<stdio.h>
int main()
{
int i=0,l,l1;
char str[100];
cout<<"enter string:";
gets(str);
while(str[i])
i++;
l=i;
for(i=0;i<=(l-1)/2;i++) //n/2 steps!!no extra memory
{
char t=str[i];
str[i]=str[l-i-1];
str[l-i-1]=t;
}
str[l]=0;
cout<<"\n\nreversed string is:"<<str;
getch();
return 0;
}

Answer / guest

char * rev(char * str){
int temp;
for(int j=0;str[j];j++);
for(int i=0;i<j;i++,j--){
temp=str[i];
str[i]=str[j];
str[j]=temp;
}
return str;
}

Answer / shruti

the above is slightly wrong
this is the corrected one..

char * rev_string (char * str)
{
char temp;
int i , j;
for (i = 0 ; str[i]!= '\0' ; i++);

for(j = 0 ; j < i ; j++ , i--)
{
temp = str[j];
str[j] = str[i];
str[i] = temp;
}

return str;
}

Answer / atul kabra

#include<stdio.h>

void reverse(char *);

void main()
{
char str[]="Hello";

reverse(str);
printf("Reverse String is %s",str);

}

void reverse(char *p)
{

char *q=p;
while(*++q!='\0');
q--;

while(p<q)
{
*p=*p+*q;
*q=*p-*q;
*p=*p-*q;
p++;
q--;
}

}

Answer / shruti

char * rev_string (char * str)
{
char temp;
int i , j;
for (i = 0 ; str[i]!= NULL ; i++);

for(j = 0 ; j < i ; j++ , i--)
{
temp = str[j];
str[j] = str[i];
str[i] = temp;
}

return str;
}

Answer / sindhuja marri

#include<stdio.h>
#incliude<conio.h>
void main()
{
char a[20]="sindhu";
int i,j,count=0;
printf("the string to be reversed is");
for(i=0;a[i]!='\0';i++)
{
printf("%c",a[i]);
count++;
}

Printf(The reverse string is");
for(j=count;j>=0;j--)
{
printf("%c",a[j]);
}
}

Answer / amaresh ch das

my_strrev(char str[Max]){
int i; // pointing to base adress
int l; //pointing to last address strlen(str) -1th position
char temp;
for(i=0,l=strlen(str)-1;i<=l; i++ ,j--)
{
temp=str[i];
str[i]=str[l];
str[l]=temp;
}
return str;
}

Answer / manoj

#include <stdio.h>


void reverse(char s[])
{
int low; /* index in the lower half of the array s */
int high; /* index in the upper half of the array s */
char c; /* for holding intermediate strings */
int len; /* the length of the string s */

/* Initialize len to the length of the string */
for (len=0;s[len]!='\0';len++) ;

/* Let low increase and high decrease until they meet */
low = 0;
high = len-1;
while (low<high) {
/* Switch the values of s[low] and s[high] */
c = s[low];
s[low] = s[high];
s[high] = c;
low++;
high--;
}
}


main()
{
int c;
char line[80]; /* array to hold a line of input */
int i; /* to use as an index in the array */

c = getchar();
i = 0;

/* Read input until EOF (CTRL-z) */
while (c != EOF) {
if (c != '\n') {
/* Put anything else but newline in the array */
line[i] = c;
i++;
}

if (c == '\n') {
/* For a newline, reverse and print the line and start new line */
line[i] = '\0';
reverse(line);
printf("%s",line);
putchar(c);
i = 0;
}

c = getchar();
}
}

Answer / imran silawat

#include<stdio.h>
#include<conio.h>
main()
{
char str[50],revstr[50];
int i=0,j=0;
printf("Enter the string to be reversed");
scanf("%s",str);
for(i=strlen(str)-1;i>=0;i--)
{
revstr[i]=str[i];
i++;
}
revstr[i]='\0';
printf("Input string : %s",str);
printf("\nOutput String : %s",revstr);
getch();
}

A program that will create a movie seat reservation. The program will display the summary seats and its status. The user will be ask what seat no. to be reserved, then it will go back again to the summary to display the updated seat status. If the seat no. is already reserved then it will prompt an error message. And also if the input seat no is out of range then it will also prompt an error message. The program is continuously running. Termination of the program will depends on how the programmer will apply. Sample output: Movie Seats Reservation Summary of Seats: Seat 1: Available Seat 2: Available Seat 3: Available Seat 4: Available Seat 5: Available Enter seat no. (Press 0 to terminate Or the assigned seat capacity) : 1 Movie Seats Reservation Summary of Seats: Seat 1: Reserve Seat 2: Available Seat 3: Available Seat 4: Available Seat 5: Available Enter seat no. (Press 0 to terminate Or the assigned seat capacity) : 6 The Seat no. is out of range! Movie Seats Reservation Summary of Seats: Seat 1: Reserve Seat 2: Available Seat 3: Available Seat 4: Available Seat 5: Available Enter seat no. (Press 0 to terminate Or the assigned seat capacity) : 1 The Seat no. is already reserved! Movie Seats Reservation Summary of Seats: Seat 1: Reserve Seat 2: Available Seat 3: Available Seat 4: Available Seat 5: Available Enter seat no. (Press 0 to terminate Or the assigned seat capacity) : 0 GoodBye... Thank You!!!

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