Answer / susie

Answer :

Definition.

x is a pointer to array of(size 10) integers.

Apply clock-wise rule to find the meaning of this definition.

#include<stdio.h> main() { const int i=4; float j; j = ++i; printf("%d %f", i,++j); }

1 Answers  

---

main() { char name[10],s[12]; scanf(" \"%[^\"]\"",s); } How scanf will execute?

2 Answers  

---

How will you print % character? a. printf(“\%”) b. printf(“\\%”) c. printf(“%%”) d. printf(“\%%”)

4 Answers   HCL,

---

1) int i=5; j=i++ + i++ + i++; printf("%d",j);This code gives the answer 15.But if we replace the value of the j then anser is different?why? 2)int i=5; printf("%d",i++ + i++ + i++); this givs 18.

8 Answers   IBPS, Infosys, TCS,

---

#define a 10 int main() { printf("%d..",a); foo(); printf("%d..",a); return 0; } void foo() { #undef a #define a 50 }

3 Answers  

---

union u { struct st { int i : 4; int j : 4; int k : 4; int l; }st; int i; }u; main() { u.i = 100; printf("%d, %d, %d",u.i, u.st.i, u.st.l); } a. 4, 4, 0 b. 0, 0, 0 c. 100, 4, 0 d. 40, 4, 0

1 Answers   HCL,

---

main() { int i=10; i=!i>14; Printf ("i=%d",i); }

1 Answers  

---

find A^B using Recursive function

2 Answers  

---

why java is platform independent?

13 Answers   Wipro,

---

Write a complete program that consists of a function that can receive two numbers from a user (M and N) as a parameter. Then print all the numbers between the two numbers including the number itself. If the value of M is smaller than N, print the numbers in ascending flow. If the value of M is bigger than N, print the numbers in descending flow. may i know how the coding look like?

2 Answers  

---

#include<stdio.h> main() { struct xx { int x=3; char name[]="hello"; }; struct xx *s; printf("%d",s->x); printf("%s",s->name); }

3 Answers   Hexaware,

---

#include<stdio.h> main() { struct xx { int x; struct yy { char s; struct xx *p; }; struct yy *q; }; }

2 Answers  

---