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main()
{
int *ptr=(int*)malloc(sizeof(int));
*ptr=4;
printf("%d",(*ptr)+++*ptr++);
}
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Answer Posted / john lee
main()
{
int *ptr=(int*)malloc(sizeof(int));
*ptr=4;
printf("%d",(*ptr)++ + (*ptr)++);
}
Like above, code should be revised as allocated memory space just has 2(16bit machine) or 4 byte(32bit machine) to save '4'.
If not, the orginal code, printf("%d",(*ptr)++ + *ptr++);
In my guess, ptr++ will be first, and then *ptr would be next.
If so, ptr++ will point to a memory address unintended(an address +2 or +4 added). And then *ptr will have a value like 0 or else.
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