Answer / sha

Consider 1 cm mortar..

so the size is .24 x .16=0.0384

num of bricks is=10/0.0384=260 nos

Answer / nirmala

earthwork excavation by manual means for foundation of buildings,culverts,water supply and sanitary lines and electrical conduits etc.either in pits or in trenches, in ordinary soil including dressing the bottom and sides of pits and trenches,stacking the excavated soil clear from edges of excavation with lead up to 50m,including breaking of clods complete as per specification ,including pumping of water,including cost of all labour,material,transport,hom of machineries,all lifts,loding and unloding .specification no KBS 2.1(a)/2.3.5.work to be completed as per the directions of the engineer in charge.
UNIT QUANTITY RATE(IN RS) AMOUNT(IN RS)
Cum 230 204 46920


please tell me the how its came quantity

Answer / sjtbehera

Brick size- 230 x115x50Consider 10 sqm - 10x.115=1.15cum 115mm th.

Normally mortar joint will be less than 1cm, taking 1cm mortar joint the actual th. Of wall thickness will be-.105mm
So, actual volume- 10x.105=1.05 cum.

No. Of bricks= 1.05/.23*.115*.150=264 nos. Take 5% wastage it comes around 280 nos.

Mortar requirement- total volume of brickwork- 1.05 cum
For fog filling, for use of cut brickwork, uniform joints take 15% extra
So total volume- 1.05+1.05*15%=1.2075

For dry volume, volume increase 1/4 th ofmortar so 1.2075+1.2075/4=1.509 cum
So for 10 sqmt 1.509 cum mortar

If you take 1:6 then you calculated cement and sand
1.509/7=.215 cum
Sand=.215x76= 1.29 cum

in staad which are the point is to be checked for not fail of structure

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