Answer / n rajesh guttedar

4.435 Bags.

Answer / ahmed

4.5 bags

Answer / kumar

1440/3 (0.45) = 216 kg = 4.32 bags

Answer / sjtbehera

let,s have calculation
for 1 cum = 1/1+3+6=.142cum total volume of conc.
then cement is = .142x1440=204.48 kg ( unit weight of
cement is 1440kg)

so bags is 204.48/50=4.08bags

it is a thumb rule

Answer / kamal deep kumar

let's have calculation
for 1 cum= 1/1+3+6=.1cum it is total volume of conc't.
then cement is=.1x1440=144kg
so bag is 144/50=2.88 bags.

it is also perfectly thumb rule.

Answer / jay

121/10
12.1/2.83= 4.27 bag

Answer / shamsideen mohammed sakwa

Bag of cements contained in ratio 1:3;6 are,
1+3+6=10
1/10=0.1*28.8bags=2.88 bags of cement
Add 50% for waste and bulk density and shrinkage
1.44+2.88=4.32 bags of cement...

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