How much current can 11KV line carry? What are the
formulae used to calculate current across both side of
transformer? Moreover I need to know can I connect 33KV
line with transformer of 1600KVA? Details are: V=415,
Pf= .9
Answers were Sorted based on User's Feedback
Answer / arulkumaran
KW = KVA*PF
KW = 1600*0.9
KW = 1440
11KV PRIMARY CURRENT=
KW = 1.732*KV*I*PF root(3) = 1.732
1440 = 1.732*11*I*0.9
1440/1.732*11*0.9 = I
I = 83.98 AMPERE
415V SECONDRY CURRENT=
WATTS = 1.732*V*I*PF
1440000 = 1.732*415*I*0.9
I = 2226 AMPERE
Is This Answer Correct ? | 80 Yes | 20 No |
Answer / manimaranmuthu.m
11KV PRIMARY CURRENT[HT]:
KW = KVA*PF
POWER [KW]= 1600*0.9
POWER = 1440 KW
POWER [KW]=√3*KV*I*PF
root(3) = 1.732
1440 = 1.732*11*I*0.9
1440/1.732*11*0.9 = I
I = 83.98 AMPERE
415V SECONDRY CURRENT[LT]:
WATTS = 1.732*V*I*PF
1440*1000 = 1.732*415*I*0.9
I = 2226 AMPERE
Is This Answer Correct ? | 29 Yes | 13 No |
Primary side voltage be 11KV,
Transformer's capacity= 1000KVA
Real power= Apparent*Power factor
KW=KVA*Power factor
if Power factor = 0.95
Power= 1000*0.95
Power=950KW
We also know,
Power(KW)=(root 3)*(KV)*I*Power factor
950=1.732*11*0.95*I
I(Current)= 49.7A
Secondary Voltage Be 433V
We know that,
Power(watts)=(root 3)*V*I*Power factor
Power=950KW=950000W
950000=1.732*433*I*0.95
I= 1333.4 A
Is This Answer Correct ? | 9 Yes | 7 No |
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