Answer / sangilisaravanan

FIN TUBES INCREASES THE SURFACE AREA OF HEATING.
SO FOR THE REQUIRED QUANTITY OF HEAT TRANSFER THE EXCHANGER
MAY BE DESIGNED SMALL IN COMPARED WITH FINLESS TUBE
EXCHANGER

Answer / s.shanmugam

Fin tubes are usually used for cooling.As we see in
automobile engines constructed with fins.

Answer / anshuman

it depends on the kind of liquid to be heated and steam
requirment if high heat transfer is required with low
cosumpsion of steam we can use fin tubes

Answer / jagadesh

it is not required to heat up liquid in fin tubes by steam
because liuid has to pass trhough tube side. so if
temperature difference is more steam will undergoes
condensation and will lead high pressure drop and less heat
transfer.

Answer / dp

It depends on the htc values on the shell side. If HTC on
the shell side is higher than the tube side adding tubes
wont make much difference in terms of total heat transfer.
If the HTC value on the tube side is higher than the shell
side, adding fins will enhance the total heat transfer. For
suppose if steam is flowing on the tube side and its phase
changes during the process its good to provide fins over the
tubes. If it is other way adding fins wont make much
difference except increasing cost of the exchanger.

Answer / ahmedcool

FINS ARE USED TO INCREASE SURFACE AREA,IS LIKELY TO
TRANSFER HEAT FROM HOTTER BODY TO COLDER BODY.FINS ARE NOT
REQUIRED IN CASE OF STEAM HEATING.

Answer / amol deshpande

Yes, fin tubes are necessary. Fin tubes increases the heat surface area and reduces the thickness of shell wall required.

what is mass flow rate of steam of 7 kg/cm2 pressure in 1 inch id. pipe.

0 Answers   Ascent,

Question 62 – The names of the flow streams could be represented by : H1 for first hot stream, H2 for second hot stream, C1 for first cold stream, C2 for second cold stream. Data of supply temperature Ts in degree Celsius : 150 for H1, 170 for H2, 30 for C1, 30 for C2. Data of target temperature Tt in degree Celsius : 50 for H1, 169 for H2, 150 for C1, 40 for C2. Data of heat capacity Cp in kW / degree Celsius : 3 for H1, 360 for H2, 3 for C1, 30 for C2. (a) Find the enthalpy changes, dH for all streams of flow H1, H2, C1 and C2 in the unit of kW. Take note of the formula dH = (Cp) (Tt - Ts). (b) Match the hot streams H1 and H2 with the suitable cold streams C1 and C2 to achieve the maximum energy efficiency.

1 Answers  

What is a good source of equations for calculating discharge flowrates from accidental releases?

0 Answers  

NATURAL GAS ENGINEERING - QUESTION 26.3 : The United States of America Energy Information Administration reports the following emissions in million metric tons of carbon dioxide in the world for year 2012 : Natural gas : 6799, petroleum : 11695, coal : 13787. Coal-fired electric power generation emits around 2000 pounds of carbon dioxide for every megawatt hour generated, which is almost double the carbon dioxide released by a natural gas-fired electric plant per megawatt hour generated. If 1 metric ton = 1000 kg and 1 pound = 0.4536 kg, estimate the total energy generated by natural gas in the world for year 2012, in gigawatt hour.

1 Answers  

Explain some common piping materials used to transport slurries?

0 Answers  

What are the reasons of removal of particles from effluent gas?

0 Answers  

What is the chemical name of Silica gel?

2 Answers  

Is there any way to remove residual product left in pipes after a batch operation?

0 Answers  

Which type of pneumatic control valve is used mostly Either Air to Open r Air to close the value And guys I need reason for your reason

0 Answers  

Dear sir/madam I am in final year BE chemical engineering.Which companies i can apply .Please guide me.It is very helpful for me

0 Answers   TCS,

ENVIRONMENTAL ENGINEERING - QUESTION 22.2 : Biochemical Oxygen Demand (BOD) could be calculated using the formula BOD = (DOi - DOf) (Vb / Vs) where Vb = Volume of bottle in ml, Vs = Volume of sample in ml, DOi = Initial dissolved oxygen in mg / L, DOf = Final dissolved oxygen in mg / L. (a) By using a bottle of Vb = 300 ml with sample Vs = 30 ml, find the BOD if DOi = 8.8 mg / L and DOf = 5.9 mg / L. (b) By using a bottle Vb = 600 mL with sample Vs = 100 mL, find the BOD if DOi = 8.8 mg / L and DOf = 4.2 mg / L. (c) Find the average BOD = [ Answer of (a) + Answer of (b) ] / 2. (d) If the BOD-5 test for (a) - (c) is run on a secondary effluent using a nitrification inhibitor, find the nitrogenous BOD (NBOD) = TBOD - CBOD. Let TBOD = 45 mg / L and CBOD = Answer of (c).

1 Answers  

Question 31 – For liquid benzene, the CP constants are : a = 129440, b = - 169.5, c = 0.64781. Reference temperature is 298 K. The temperature of benzene is 60 degree Celsius. Calculate the enthalpy of benzene by using the formula H = a (DT) + (b/2) (T^2 – TREF^2) + (c/3) (T^3 – TREF^3) where ^ is power, DT is temperature difference with TREF = 298 K. H is in J / kmol. DT = T – TREF.

1 Answers