Answer / k.amirthalingam

Quantity of material used for a Hollow block work
(400X200X200)?

1. Qty of HOllow block is 10 to 12 numbers / Sqm
2. Cement sand ratio preferable is 1:4
3. For 1:4 CM the cement, sand calculation as follows

Volume of mortor = Horizontal joints 5 rows of 200 mm wide
20 mm thick = 5*.2*.02 = .02 cum

Volume of verticaljoints : 5*2.5*.2*.2*.02 = .01 cum

Total = .03 + 30 % wastage = 0.039 Cum of Cement Mortor

For 1:4 ratio

Weight of cement in 1 Sqm = .039*1*(1/5)*1440 = 11.232
Kg /Sqm

Volume of Sand = .039*1*(4/5) = .0312 Cum = 1.11 Cubic foot


NOTE: But in actual it occurs more than the above
calculated values because many unskilled people filling the
hollow portions of the block. This is the wrong practice.
The Laying system is such that the hollow portion to be
overlapped with filled portion hence the hollow portion to
be maintained. This will give good heat reduction inside
the building.

For more queris mail me at ameerabic@gmail.com

K.Amirthalingam from Ariyalur

Answer / balamurugan

1.Qty of Hollow block is 11 to 12 Nos/ sqm
2.For 9" wide wall Cement sand ratio is 1:6 & 4" wide wall
Cement sand ratio is 1:4.

Volume of mortar/Sqm = (No of Blocks required for the size
of without mortar thick -No of Blocks required for the size
of block including mortar thick)x No of Blocks required for
the actual size of block

For 9" wall

No of Blocks required for the size of without mortar
thick=1/(0.40*.20*.20)=62.5
No of Blocks required for the size of block including mortar
thick= 1/(0.41*.21*0.21)=53.31 Nos

Volume of mortar/Cum= [62.5-55.31]x[0.4x0.2*0.2]
=0.115 Cum
Add wastage 30% extra

Volume of mortar/Cum= 0.115*30% =0.150Cum

Cement sand calculation/Cum of Block work:

Ratio 1:6

Cement =[1/7*1440]*.150 =31Kg
Sand =[(6/7)*.15]=0.129Cum =4.55 Cft

Cement sand calculation/Sqm of Block work:

Ratio 1:6

Cement =[1/7*1440]*.15*.23 =7.13Kg
Sand =[(6/7)*.15*.23]=0.03Cum =1.05Cft

Answer / estimator

1. the quantity of CHB required per sq.m. is equal to area to be filled divided by the area of CHB
= 1 sqm / ( 0.4x0.2 ) = 12.5 CHB, approx. 13 CHB (16"x8"x8)
2. computing the mortar required using the density of 1 bag of portland cement (1506 kg/cu.m) and density of dry sand (1602 kg/ cu.m)
* volume of mortar horizontal joint = 5row x 0.2m x 1.0m x 0.01m = 0.01cu.m
* volume of mortar vertical joint = 4row x 0.2m x 1.0m x 0.01m = 0.008cu.m
* total mortar required = 0.01 + 0.008 = 0.018cu.m
3. using the commonly used ratio for making a good mortar 1:3,
* quantity of cement required = 1/4 (density of cement x total vol of mortar) = 1/4(1506x0.018) = 6.78kgs
* quantity of dry sand required = 3/4 (density of dry sand x total vol of mortar) = 3/4(1602x0.018) = 21.63kgs

Answer / s.dhote

how much quantity of blocks,cement and sand is required to complete 1sq.m of cc solid blockswork.size 2'*8"*8".also what is the cement sand ratio commonly used?

Answer / er.k.pratabchandran

BLOCK SIZE :390*190*190MM(ON MUSCAT)

WITHOUT C.M NOOFBLOCK IS=1/(0.39*0.19*0.19)=71NOS

WITH C.M NOOFBLOCKS IS=1/(0.40*0.20*0.20)=62.5NOS

C.M=(71-62.5)=8.5NOS*(0.39*0.19*0.19)=0.119CUM

REQUIREMENT FOR C.M1:5=1/5*1440=288KG=5.76BAGS/CUM

FOR 0.119CUM=5.76*0.119=0.68BAGS(WITHOUT WASTAGE)

FOR SAND C.M=1/5*1.57(FACTOR FOR FINESAND)=0.314CUM

FOR 0.119CUM=0.314*0.119=0.037CUM=1.30CFT(0.037*35.315=1.30CFT)

Answer / alpesh patel

how many cement& sand consumption for 600*200*200 light weight block (1:5 ratio)in 1m3

Answer / saikat roy

Above all 2 ans should be factored with 1.4 for wet to dry volume conversion.

Answer / p mathan kumar b.e.,

1. I have used light weights block sizes 590*200*200
2. Volume Mortar = (42.3-37.8) *0.59*0.2*0.2
3. 1.06 cu.m
4. Mortar ratio 1:4
5. Volume of cement = 1.06*1/5=0.0213 cu.m*1440=30.58 kg
6. Volume of sand= 1.06*4/5=0.848 cum

Answer / janani

Blocks-37 nos
Cement-1.6 bags
Sand-9.88cft

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