Answer / janava

In this a variable is a integer but read the int as char so
it shows error.
this can be written as
#include<stdio.h>
#include<conio.h>
void main()
{
int a;
printf("\n Enter a number");
scanf("%d",&a);
getch();
}

Answer / lalithpriya

#include<stdio.h>
#include<conio.h>
void main()
{
int a;
clrscr();
printf("Enter a number:");
scanf("%d",&a);
printf("The entered number is %d",a);
getch();
}

Answer / r.kumar bsc

getting a value is defined %d that is scanf("%d\n");
this formatted is correct that %c is defined only is
getting the characters.

Answer / aarti

#include<stdio.h>
#include<conio.h>
void main
{
clrscr();
int number;
printf("\n enter a number:");
scanf("%d",&number);
getch();
}

Answer / pawanjha12

Here in the scanf("%c\n");
it is just take a input. and, it will store that input
value anywhere.
it would be just garbage value. ok.........
nothing is output.
say, null pointer assignment.........

Answer / gaurav tyagi

there is a error in program because ""is use in headerfile
due to this compiler is search the conio.h&stdio.h file in current directory
note:<>is use to tell compiler find these file in system area

Answer / aarti

#include<stdio.h>
#include<conio.h>
void main()
{
int number;
clrscr();
printf("\n enter a number:");
scanf("%d",&number);
getch();
}

Answer / mohit

#include {studio h}
#include{conio h}
[void main]

Answer / sansiri

it access the value but it doesnot assign for any variable

Answer / lodu

#INCLUDE<STDIO.H>
#INCLUDE<CONIO.H>
{
VOID MAIN()
{
INT X,Y,Z;

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