Find the error (2.5*2=5) (a) X=y=z=0.5,2.0-5.75 (b) s=15;

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Given an int variable n that has already been declared and initialized to a positive value, and another int variable j that has already been declared, use a do...while loop to print a single line consisting of n asterisks. Thus if n contains 5, five asterisks will be printed. Use no variables other than n and j .

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Given an int variable n that has been initialized to a positive value and, in addition, int variables k and total that have already been declared, use a do...while loop to compute the sum of the cubes of the first n whole numbers, and store this value in total . Thus if n equals 4, your code should put 1*1*1 + 2*2*2 + 3*3*3 + 4*4*4 into total . Use no variables other than n , k , and total .

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when i use cout or cin call & then either << or >> .....it shows declaration syntax error...what should i do? cout<<"anything"; int a; cin>>a; return 0;

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How to reverse a linked list without using array & -1? Thank you.

2 Answers   Access, Satyam,

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void main() { int i=5; printf("%d",i+++++i); }

14 Answers   HCL,

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what is meant for variable not found?

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Declaration of Cube Guys please help me.. Is this a right way to declare cube.? If i Compile it. It Says: Cube undeclared what should i do? Please help \thanks in advanced #include<stdio.h> #include<math.h> #include<conio.h> main( ) { float x,y; while(x++<10.0) { printf("Enter Number:"); scanf("%d", &x); y = cube(x); printf("%f %f %f \n", x,pow(x,2),y); cube(x); } { float x; float y; y = x*x*x; } getch(); return (y); }

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I can not get my C++ program to work right. It is supposed to tell if a word is a palindrome or not, but it only tells thet the word is not a palindrome. And I can't fix it.

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void main() { for(int i=0;i<5;i++); printf("%d",i); } What is the output?..

32 Answers   College School Exams Tests, CTS, HCL, iGate, SmartData,

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what is syntax error?

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How to create a program that lists the capital country when told what the original country is? (Terribly sorry, I'm a novice programmer and would appreciate any help ;). Cheers, Alexxis

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