WHAT WILL BE THE OUTPUT OF THE FOLLOWING QUESTION
void main()
{
int x=4,y=3,z;
z=x-- -y;
printf("%d%d%d",x,y,z);
}
Answers were Sorted based on User's Feedback
Answer / shreyas
the answer is 3 3 1..........
while computing value of z ....x will be 4 .....but while
printing its value it has been decremented by 1 and hence x=3.
| Is This Answer Correct ? | 42 Yes | 2 No |
Absolutely.. 3 3 1
No doubt in it.....all frnds who said it are right and their
explaination is also correct......
while Z is calculated X is 4...since it is post decrement....
| Is This Answer Correct ? | 12 Yes | 3 No |
Answer / amrita mohanty
3,3,1
since it is a post increment operation,so x--=4 initially.
but after that the value of x becomes 3.
x-- - y = 4-3=1
therefore x=3,y=3,z=1
| Is This Answer Correct ? | 9 Yes | 0 No |
Answer / anjana priyadharshini
THE OUTPUT IS: 3,3,1
THE PEOPLE WHO TOLD THIS ANSWER THEIR EXPLANATION IS CORRECT
| Is This Answer Correct ? | 5 Yes | 0 No |
Answer / medo
#include<stdio.h>
void main()
{ int x,y,z;
{
int x=4,y=3,z;
z=x---y;
printf("x=%d\ny=%d\nz=%d\n",x,y,z);
}
}
| Is This Answer Correct ? | 3 Yes | 1 No |
Answer / vishnu
initally x=4,y=3
z=x-- -y;
after doing x-y operation and that value wil be assigned to
z.there followed by x value wil be decreased by 1.
hence z=4-3 z=1
x=4-1 x=3
y=3
hence output will be
3,3,1
| Is This Answer Correct ? | 2 Yes | 0 No |
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