What is the out put of this programme?
int a,b,c,d;
printf("Enter Number!\n");
scanf("%d",&a);
while(a=!0)
{
printf("Enter numbers/n");
scanf("%d%d%d",&b,&c,&d);
a=a*b*c*d;
}
printf("thanks!");
getche();
Entering numbers are
a=1,b=2,c=3,d=4
b=3,c=4,d=-5
b=3,c=4,d=0
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Answer / michael
Enter Number
1
Enter numbers
234
Enter numbers
34-5
Enter numbers
340thanks!
| Is This Answer Correct ? | 5 Yes | 2 No |
Answer / nagendra kumar
hat is the out put of this programme?
int a,b,c,d;
printf("Enter Number!\n");
scanf("%d",&a);
while(a=!0)
{
printf("Enter numbers/n");
scanf("%d%d%d",&b,&c,&d);
a=a*b*c*d;
}
printf("thanks!");
getche();
Entering numbers are
a=1,b=2,c=3,d=4
answer: thanks
| Is This Answer Correct ? | 5 Yes | 2 No |
Answer / sansiri
Enter Number!
1
Enter numbers/n2 3 4
Enter numbers/n3 4 -5
Enter numbers/n3 4 0
thanks!
| Is This Answer Correct ? | 1 Yes | 0 No |
Answer / susan
It will goes to infinite loop i.e. while of true condition executes if a!=0
| Is This Answer Correct ? | 0 Yes | 0 No |
#include"stdio.h" #include"conio.h" void main() { int a; printf("\n enter a number:"); scanf("%c\n"); getch(); }
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