Answer / michael

Enter Number
1
Enter numbers
234
Enter numbers
34-5
Enter numbers
340thanks!

Answer / nagendra kumar

hat is the out put of this programme?
int a,b,c,d;

printf("Enter Number!\n");
scanf("%d",&a);
while(a=!0)

{
printf("Enter numbers/n");
scanf("%d%d%d",&b,&c,&d);
a=a*b*c*d;

}
printf("thanks!");

getche();

Entering numbers are
a=1,b=2,c=3,d=4



answer: thanks

Answer / sansiri.r

Enter Number!
1
Enter numbers
2 3 4
Enter numbers
3 4 -5
Enter numbers
3 4 0
thanks!

Answer / sansiri

Enter Number!
1
Enter numbers/n2 3 4
Enter numbers/n3 4 -5
Enter numbers/n3 4 0
thanks!

Answer / susan

It will goes to infinite loop i.e. while of true condition executes if a!=0

how to convert decimal to binary in c using while loop without using array

50 Answers   Apple, Aptech, Arwen Tech, BCS, C2D Software, CEC,

---

what is run time error?

7 Answers  

---

loop1: { x=i<n?(i++):0; printf("%d",i); exit(x); continue; } Error- misplaced continue. Doubt-1.will the exit(x) be executed for all values of x 2.will this statement go out of the program.

5 Answers   CMC,

---

errors are known as?

3 Answers   EX, State Bank Of India SBI,

---

WHAT WILL BE THE OUTPUT OF THE FOLLOWING QUESTION void main() { int x=4,y=3,z; z=x-- -y; printf("%d%d%d",x,y,z); }

25 Answers   HCL,

---

---

I can not get my C++ program to work right. It is supposed to tell if a word is a palindrome or not, but it only tells thet the word is not a palindrome. And I can't fix it.

1 Answers  

---

What is the out put of this programme? int a,b,c,d; printf("Enter Number!\n"); scanf("%d",&a); while(a=!0) { printf("Enter numbers/n"); scanf("%d%d%d",&b,&c,&d); a=a*b*c*d; } printf("thanks!"); getche(); Entering numbers are a=1,b=2,c=3,d=4 b=3,c=4,d=-5 b=3,c=4,d=0

5 Answers   TCS,

---

quoroum of computer languages?

0 Answers   Infosys,

---

difference between c/c++ programing language? what is necessesity of c++ when existing c programing language?

2 Answers   TCS,

---

void main() { int i=5,y=3,z=2,ans; clrscr(); printf("%d",++i + --z + i++ + --i * ++y); i=5,y=3,z=2; ans=++i + --z + i++ + --i * ++y; printf("\n%d",ans); getch(); } Its output is 37 and 31.... Please explain me why its different How it works.....

2 Answers  

---

What are the different types of errors in C and when they occur?

4 Answers  

---

#include<iostream.h> #include<stdlib.h> static int n=0; class account { int age,accno; float amt; char name[20]; public: friend void accinfo(account [] ,int); void create(); void balenq(); void deposite(); void withdrawal(); void transaction(account []); }; void account :: create() { static int acc=1231; accno=acc+n; cout<<"\n\tENTER THE CUSTOMER NAME : "; cin>>name; cout<<"\n\t ENTER THE AGE : "; cin>>age; cout<<"\n\t ENTER THE AMOUNT : "; cin>>amt; // if(amt<=500) // cout<<"\n\tAMOUNT IS NOT SUFFICIENT TO CREATE AN ACCOUNT..."; cout<<"\n\t YOUR ACCOUNT NUMBER : "<<accno<<endl; n++; } void accinfo(account cus[],int ch) { int no,flag=0; cout<<"\n\t\tENTER YOUR ACCOUNT NUMBER : "; cin>>no; for(int i=0;i<=n&&flag==0;i++) if(no==cus[i].accno) { flag=1; switch(ch) { case 2: cus[i].balenq(); break; case 3: cus[i].deposite(); break; case 4: cus[i].withdrawal(); break; case 5: cus[i].transaction(cus); break; default: cout<<"\n\t\tEND OF THE OPERATION"; exit(1); } } if(flag==0) cout<<"\n\t\tYOUR ACCOUNT DOES NOT EXIST..."<<endl; } void account :: balenq() { cout<<"\n\t\tCUSTOMER NAME : "<< name << endl; cout<<"\n\t\tBALANCE : "<< amt << endl; } void account :: deposite() { int damt; cout<<"\n\t\tCUSTOMER NAME : "<< name <<endl; cout<<"\n\t\tBALANCE : "<< amt <<endl; cout<<"\n\tENTER THE AMOUNT TO BE DEPOSITED : "; cin>>damt; amt+=damt; cout<<"\n\t\tYOUR CURRENT BALANCE : "<<amt<<endl; } void account :: withdrawal() { int wamt; cout<<"\n\t\tCUSTOMER NAME : "<< name; cout<<"\n\t\tBALANCE : "<< amt; cout<<"\n\tENTER THE AMOUNT TO BE WITHDRAWN : "; cin>>wamt; if(amt-wamt>=500) { amt-=wamt; cout<<"\n\t\tYOUR CURRENT BALANCE : "<<amt; } else cout<<"\n\tYOUR BALANCE IS TOO LOW FOR WITHDRAWAL..."<<endl; } void account :: transaction (account cus[]) { int no,tamt,flag=0; cout<<"\n\tENTER THE RECEIVER'S ACCOUNT NUMBER : "; cin>>no; cout<<"\n\t\t ENTER THE AMOUNT : "; cin>>tamt; for(int i=0;i<=n&&flag==0;i++) if(cus[i].accno==no) { flag=1; cus[i].amt+=tamt; amt-=tamt; cout<<"\n\t\tYOUR CURRENT BALANCE : "<<amt<<endl; cout<<"\n\t\t RECEIVER'S BALANCE : "<<cus[i].amt<<endl; } if(flag==0) cout<<"\n\tRECEIVER'S ACCOUNT NUMBER IS NOT AVALIABLE..."<<endl; } void main() { account cus[10]; int ch; do { cout<<"\n\t\t BANK ACCOUNT"; cout<<"\n\t\t ************\n"; cout<<"\n\t\t1.CREATE AN ACCOUNT"; cout<<"\n\t\t2.BALANCE ENQUIRY"; cout<<"\n\t\t3.DEPOSITE"; cout<<"\n\t\t4.WITHDRAWAL"; cout<<"\n\t\t5.TRANSACTION"; cout<<"\n\t\t6.EXIT\n\n"; cout<<"\n\t\tENTER YOUR CHOICE : "; cin>>ch; if(ch==1) cus[n].create(); else accinfo(cus,ch); }while(1); }

1 Answers  

---