Answer / ravi

NO ERRORS but result...........

Answer / rakesh

in this question whenever the loop excuted getch() take
input after that next loop is excuted and similar getch()
take another input
that think do untill the conditions of c<='z' is not
completed

Answer / sujeesh krishnan

The initial condition is c='A'.
Here the the statement "getch();" is the body of the loop.
it is executed once and c becomes 'B' and again the loop is
executed.
This is done,I mean the loop is executed 26 times.
when c become 'Z' the loop is executed one more time(because
the condition is c<='Z')and then the program exit.

Answer / vignesh1988i

this wont show any errors since syntactically it is correct...
but since there is no instructions after for loop for operations unfortunelety getch() will be taken as the next instruction , and thus compiler system will be under ambiquity. since the character key pressed will be taken as the value of getch() so that will say to the OPERATING SYSTEM that compilation has got over and it will return to the IDE... but for loop has not got over.. so this depends on the compilers usage............



thank u

Answer / aaaaaaa

No Errors
loop will execute for 26 times,each time it will wait for an
input and finally terminate when c becomes > Z.

Answer / sambath

Answer : "It have no errors but it will be still running
mode until use cntrl+break.. using { and } we will avoid this."

Answer / abhishek rajput

Since A=65 and Z=90.
So each time getch will
encounter and user
need to press anykey
each time till c
increments to 90...

Answer / carlos

God help those who help themselves!
try it ur's self because i don't know about this programming
brother! i'm sorry forgive me.

Answer / bharghavi

if ther s no body for the 'for' loop,it should end with
semicolon..(i.e)
main()
{
char c;
for(c='A';c<='Z';c++);
getch();
}
or
main()
{
char c;
for(c='A';c<='Z';c++)
{}
getch();
}

Write a C program to enter 10 integer numbers through one variable and count how many of them are even using while loop ?

2 Answers  

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3 Answers  

#include<iostream.h> #include<stdlib.h> static int n=0; class account { int age,accno; float amt; char name[20]; public: friend void accinfo(account [] ,int); void create(); void balenq(); void deposite(); void withdrawal(); void transaction(account []); }; void account :: create() { static int acc=1231; accno=acc+n; cout<<"\n\tENTER THE CUSTOMER NAME : "; cin>>name; cout<<"\n\t ENTER THE AGE : "; cin>>age; cout<<"\n\t ENTER THE AMOUNT : "; cin>>amt; // if(amt<=500) // cout<<"\n\tAMOUNT IS NOT SUFFICIENT TO CREATE AN ACCOUNT..."; cout<<"\n\t YOUR ACCOUNT NUMBER : "<<accno<<endl; n++; } void accinfo(account cus[],int ch) { int no,flag=0; cout<<"\n\t\tENTER YOUR ACCOUNT NUMBER : "; cin>>no; for(int i=0;i<=n&&flag==0;i++) if(no==cus[i].accno) { flag=1; switch(ch) { case 2: cus[i].balenq(); break; case 3: cus[i].deposite(); break; case 4: cus[i].withdrawal(); break; case 5: cus[i].transaction(cus); break; default: cout<<"\n\t\tEND OF THE OPERATION"; exit(1); } } if(flag==0) cout<<"\n\t\tYOUR ACCOUNT DOES NOT EXIST..."<<endl; } void account :: balenq() { cout<<"\n\t\tCUSTOMER NAME : "<< name << endl; cout<<"\n\t\tBALANCE : "<< amt << endl; } void account :: deposite() { int damt; cout<<"\n\t\tCUSTOMER NAME : "<< name <<endl; cout<<"\n\t\tBALANCE : "<< amt <<endl; cout<<"\n\tENTER THE AMOUNT TO BE DEPOSITED : "; cin>>damt; amt+=damt; cout<<"\n\t\tYOUR CURRENT BALANCE : "<<amt<<endl; } void account :: withdrawal() { int wamt; cout<<"\n\t\tCUSTOMER NAME : "<< name; cout<<"\n\t\tBALANCE : "<< amt; cout<<"\n\tENTER THE AMOUNT TO BE WITHDRAWN : "; cin>>wamt; if(amt-wamt>=500) { amt-=wamt; cout<<"\n\t\tYOUR CURRENT BALANCE : "<<amt; } else cout<<"\n\tYOUR BALANCE IS TOO LOW FOR WITHDRAWAL..."<<endl; } void account :: transaction (account cus[]) { int no,tamt,flag=0; cout<<"\n\tENTER THE RECEIVER'S ACCOUNT NUMBER : "; cin>>no; cout<<"\n\t\t ENTER THE AMOUNT : "; cin>>tamt; for(int i=0;i<=n&&flag==0;i++) if(cus[i].accno==no) { flag=1; cus[i].amt+=tamt; amt-=tamt; cout<<"\n\t\tYOUR CURRENT BALANCE : "<<amt<<endl; cout<<"\n\t\t RECEIVER'S BALANCE : "<<cus[i].amt<<endl; } if(flag==0) cout<<"\n\tRECEIVER'S ACCOUNT NUMBER IS NOT AVALIABLE..."<<endl; } void main() { account cus[10]; int ch; do { cout<<"\n\t\t BANK ACCOUNT"; cout<<"\n\t\t ************\n"; cout<<"\n\t\t1.CREATE AN ACCOUNT"; cout<<"\n\t\t2.BALANCE ENQUIRY"; cout<<"\n\t\t3.DEPOSITE"; cout<<"\n\t\t4.WITHDRAWAL"; cout<<"\n\t\t5.TRANSACTION"; cout<<"\n\t\t6.EXIT\n\n"; cout<<"\n\t\tENTER YOUR CHOICE : "; cin>>ch; if(ch==1) cus[n].create(); else accinfo(cus,ch); }while(1); }

1 Answers  

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