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void main()
{
int i=7;
printf("N= %*d",i,i);
}

Question Posted / snup24

Answers were Sorted based on User's Feedback



void main() { int i=7; printf("N= %*d",i,i); }..

Answer / pawanjha12

Its output would be 7,

"%*d"

here * symbol doesn't affect of operation of %d.

so 7 is set to value in variable i.

Is This Answer Correct ?    19 Yes 6 No

void main() { int i=7; printf("N= %*d",i,i); }..

Answer / munir

N= 7
Six space will be left and than 7 will be written..* is kind
of width...so if you put printf("N=$3d,i) than width will be
set as 3.
inshort * is kind used when setting up the width..

Is This Answer Correct ?    8 Yes 5 No

void main() { int i=7; printf("N= %*d",i,i); }..

Answer / vishal bhardwaj

it will display N= 7

Is This Answer Correct ?    1 Yes 1 No

void main() { int i=7; printf("N= %*d",i,i); }..

Answer / sansiri

N= 7




it doesnot consider the * symbol and the other i.

Is This Answer Correct ?    0 Yes 0 No

void main() { int i=7; printf("N= %*d",i,i); }..

Answer / rohit kiran

The Output is:
N=7

Is This Answer Correct ?    2 Yes 3 No

void main() { int i=7; printf("N= %*d",i,i); }..

Answer / sapna

garbage value

Is This Answer Correct ?    2 Yes 5 No

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