Answer / susie

Explanation:

i is an unsigned integer. It is compared with a signed
value. Since the both types doesn't match, signed is
promoted to unsigned value. The unsigned equivalent of -2 is
a huge value so condition becomes false and control comes
out of the loop.

Answer / maroti kukade

No output

What is the subtle error in the following code segment? void fun(int n, int arr[]) { int *p=0; int i=0; while(i++<n) p = &arr[i]; *p = 0; }

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why java is platform independent?

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4 Answers  

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