Answer / susie

Answer : & Explanation:

If the body of the loop never executes p is assigned no
address. So p remains NULL where *p =0 may result in problem
(may rise to runtime error “NULL pointer assignment” and
terminate the program).

void main() { int x,y=2,z; z=(z*=2)+(x=y=z); printf("%d",z); }

4 Answers  

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main() { char c=' ',x,convert(z); getc(c); if((c>='a') && (c<='z')) x=convert(c); printf("%c",x); } convert(z) { return z-32; }

1 Answers  

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Write a complete program that consists of a function that can receive two numbers from a user (M and N) as a parameter. Then print all the numbers between the two numbers including the number itself. If the value of M is smaller than N, print the numbers in ascending flow. If the value of M is bigger than N, print the numbers in descending flow. may i know how the coding look like?

2 Answers  

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How will u find whether a linked list has a loop or not?

8 Answers   Microsoft,

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how to test pierrot divisor

0 Answers  

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void main() { unsigned giveit=-1; int gotit; printf("%u ",++giveit); printf("%u \n",gotit=--giveit); }

1 Answers  

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#define a 10 int main() { printf("%d..",a); foo(); printf("%d..",a); return 0; } void foo() { #undef a #define a 50 }

3 Answers  

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Which version do you prefer of the following two, 1) printf(“%s”,str); // or the more curt one 2) printf(str);

1 Answers  

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main() { char *a = "Hello "; char *b = "World"; clrscr(); printf("%s", strcat(a,b)); } a. Hello b. Hello World c. HelloWorld d. None of the above

3 Answers   HCL,

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#define SQR(x) x * x main() { printf("%d", 225/SQR(15)); } a. 1 b. 225 c. 15 d. none of the above

3 Answers   HCL,

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Given a list of numbers ( fixed list) Now given any other list, how can you efficiently find out if there is any element in the second list that is an element of the first list (fixed list)

3 Answers   Disney, Google, ZS Associates,

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main() { char *p="GOOD"; char a[ ]="GOOD"; printf("\n sizeof(p) = %d, sizeof(*p) = %d, strlen(p) = %d", sizeof(p), sizeof(*p), strlen(p)); printf("\n sizeof(a) = %d, strlen(a) = %d", sizeof(a), strlen(a)); }

1 Answers  

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