Answer / susie

Answer :

Compiler error: Lvalue required in function main

Explanation:

++i yields an rvalue. For postfix ++ to operate an lvalue
is required.

write the function. if all the character in string B appear in string A, return true, otherwise return false.

11 Answers   Google,

---

#include"math.h" void main() { printf("Hi everybody"); } if <stdio.h> will be included then this program will must compile, but as we know that when we include a header file in "" then any system defined function find its defination from all the directrives. So is this code of segment will compile? If no then why?

2 Answers  

---

main() { char *p; p="%d\n"; p++; p++; printf(p-2,300); }

1 Answers  

---

what will be the output of this program? void main() { int a[]={5,10,15}; int i=0,num; num=a[++i] + ++i +(++i); printf("%d",num); }

3 Answers   Wipro,

---

what is the code of the output of print the 10 fibonacci number series

2 Answers  

---

main() { int i=10; i=!i>14; Printf ("i=%d",i); }

1 Answers  

---

Write a complete program that consists of a function that can receive two numbers from a user (M and N) as a parameter. Then print all the numbers between the two numbers including the number itself. If the value of M is smaller than N, print the numbers in ascending flow. If the value of M is bigger than N, print the numbers in descending flow. may i know how the coding look like?

2 Answers  

---

given integer number,write a program that displays the number as follows: First line :all digits second line : all except the first digit . . . . Last line : the last digit

8 Answers  

---

pls anyone can help me to write a code to print the values in words for any value.Example:1034 to print as "one thousand and thirty four only"

2 Answers  

---

main() { int x=5; clrscr(); for(;x==0;x--) { printf("x=%d\n”", x--); } } a. 4, 3, 2, 1, 0 b. 1, 2, 3, 4, 5 c. 0, 1, 2, 3, 4 d. none of the above

3 Answers   HCL,

---

main() { char *p; printf("%d %d ",sizeof(*p),sizeof(p)); }

6 Answers  

---

#include<stdio.h> main() { int a[2][2][2] = { {10,2,3,4}, {5,6,7,8} }; int *p,*q; p=&a[2][2][2]; *q=***a; printf("%d..%d",*p,*q); }

1 Answers  

---