int DIM(int array[])
{
return sizeof(array)/sizeof(int );
}
main()
{
int arr[10];
printf(“The dimension of the array is %d”, DIM(arr));
}
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Answer / susie
Answer :
1
Explanation:
Arrays cannot be passed to functions as arguments and only
the pointers can be passed. So the argument is equivalent to
int * array (this is one of the very few places where [] and
* usage are equivalent). The return statement becomes,
sizeof(int *)/ sizeof(int) that happens to be equal in this
case.
| Is This Answer Correct ? | 9 Yes | 2 No |
Answer / manoj kumar
Arrays cannot be passed to functions as arguments and only
the pointers can be passed.
| Is This Answer Correct ? | 3 Yes | 0 No |
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