Answer / ajay karanam

a. Runtime error.

Answer / deepesh sharma

The Answer is
a) Runtime Error.

Details: hello world is a constant string and the address of
the memory location where this string is stored is assigned
to p. In second line you are changing the value at that
address which is constant string hence changing a constant
is runtime error.

Answer / guest

b) Hello world

Answer / sandeep

answer:

Hello word

Answer / vijayanand yadav ("appu s

compile time error,
because of the semi colon present in the variable char *p="hello world";p[0]='H';here in this example the semi colon is just replaced with a , operator....

main() { int i=5,j=6,z; printf("%d",i+++j); }

2 Answers  

void main() { while(1){ if(printf("%d",printf("%d"))) break; else continue; } }

1 Answers  

Cau u say the output....?

1 Answers  

What is the output of the program given below main() { signed char i=0; for(;i>=0;i++) ; printf("%d\n",i); }

1 Answers  

main() { int a=10,*j; void *k; j=k=&a; j++; k++; printf("\n %u %u ",j,k); }

1 Answers  

Is this code legal? int *ptr; ptr = (int *) 0x400;

1 Answers  

You are given any character string. Find the number of sets of vowels that come in the order of aeiou in the given string. For eg., let the given string be DIPLOMATIC. The answer returned must be "The number of sets is 2" and "The sets are "IO and AI". Vowels that form a singleton set must be neglected. Try to post the program executable in gcc or g++ or in java.

3 Answers  

write a program to count the number the same (letter/character foreg: 's') in a given sentence.

2 Answers  

Write a C program that defines a 2-dimentional integer array called A [50][50]. Then the elements of this array should randomly be initialized either to 1 or 0. The program should then print out all the elements in the diagonal (i.e. a[0][0], a[1][1],a[2][2], a[3][3], ……..a[49][49]). Finally, print out how many zeros and ones in the diagonal.

2 Answers  

Give a very good method to count the number of ones in a 32 bit number. (caution: looping through testing each bit is not a solution)

7 Answers   Microsoft,

main ( ) { static char *s[ ] = {“black”, “white”, “yellow”, “violet”}; char **ptr[ ] = {s+3, s+2, s+1, s}, ***p; p = ptr; **++p; printf(“%s”,*--*++p + 3); }

1 Answers  

void main() { int i=i++,j=j++,k=k++; printf(“%d%d%d”,i,j,k); }

1 Answers