Answer / susie

Answer :

Compiler error: Lvalue required in function main

Explanation:

Array names are pointer constants. So it cannot be
modified.

Answer / manju

Its an error since names contains strings they cannot be
assigned like this.

void main() { int k=ret(sizeof(float)); printf("\n here value is %d",++k); } int ret(int ret) { ret += 2.5; return(ret); }

1 Answers  

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Hi, i have a project that the teacher want a pyramid of numbers in C# or java...when we click a button...the pyramid should be generated in a listbox/or JtextArea...and the pyramid should have the folowing form: 1 232 34543 4567654 567898765 67890109876 7890123210987 890123454321098 90123456765432109 0123456789876543210 Plz help with codes...didn't find anything on the net.

0 Answers  

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#define FALSE -1 #define TRUE 1 #define NULL 0 main() { if(NULL) puts("NULL"); else if(FALSE) puts("TRUE"); else puts("FALSE"); }

1 Answers  

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program to find magic aquare using array

4 Answers   HCL,

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void func1(int (*a)[10]) { printf("Ok it works"); } void func2(int a[][10]) { printf("Will this work?"); } main() { int a[10][10]; func1(a); func2(a); } a. Ok it works b. Will this work? c. Ok it worksWill this work? d. None of the above

1 Answers   HCL,

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union u { struct st { int i : 4; int j : 4; int k : 4; int l; }st; int i; }u; main() { u.i = 100; printf("%d, %d, %d",u.i, u.st.i, u.st.l); } a. 4, 4, 0 b. 0, 0, 0 c. 100, 4, 0 d. 40, 4, 0

1 Answers   HCL,

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You are given any character string. Find the number of sets of vowels that come in the order of aeiou in the given string. For eg., let the given string be DIPLOMATIC. The answer returned must be "The number of sets is 2" and "The sets are "IO and AI". Vowels that form a singleton set must be neglected. Try to post the program executable in gcc or g++ or in java.

3 Answers  

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main() { printf("%d", out); } int out=100;

3 Answers  

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main() { char a[4]="HELLO"; printf("%s",a); }

3 Answers   CSC,

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main( ) { int a[2][3][2] = {{{2,4},{7,8},{3,4}},{{2,2},{2,3},{3,4}}}; printf(“%u %u %u %d \n”,a,*a,**a,***a); printf(“%u %u %u %d \n”,a+1,*a+1,**a+1,***a+1); }

2 Answers  

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void main() { int x,y=2,z; z=(z*=2)+(x=y=z); printf("%d",z); }

4 Answers  

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main() { float me = 1.1; double you = 1.1; if(me==you) printf("I love U"); else printf("I hate U"); }

1 Answers  

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