Answer / sachinb

Give me answer

Answer / p.pratyusha

#include<iostream.h>
#include<conio.h>
void main()
{
clrscr();
int i=5,q,n=-1,r;
for(q=0;q<i;q++)
{
char ch='A';
for(int j=0;j<i;j++)
{
cout<<ch;
++ch;
}
if(n>0)
{
for(int k=n;k>0;k--)
{
cout<<" ";
}
}
for(r=0;r<i-1;r--)
{
ch--;
cout<<ch;

}
cout<<endl;
n+=2;
--i;
}
}

void main() { while(1){ if(printf("%d",printf("%d"))) break; else continue; } }

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Printf can be implemented by using __________ list.

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