main()

{

int i;

clrscr();

for(i=0;i<5;i++)

{

printf("%d\n", 1L << i);

}

}

a. 5, 4, 3, 2, 1

b. 0, 1, 2, 3, 4

c. 0, 1, 2, 4, 8

d. 1, 2, 4, 8, 16

Answers were Sorted based on User's Feedback



main() { int i; clrscr(); for(i=0;i<5;i++) { printf("%d\..

Answer / thilaga

Clearly ans is d.
1<<0 times is 0001.so in decimal 1.
1<<1 times is 0010.so in decimal 2.
1<<2 times is 0100.so in decimal 4.
1<<3 times is 1000.so in decimal 8.
1<<4 times is 0001 0000.so in decimal 16.
thus it becomes 1,2,4,8,16.

Is This Answer Correct ?    24 Yes 2 No

main() { int i; clrscr(); for(i=0;i<5;i++) { printf("%d\..

Answer / guest

d) L does't make any diff.

Is This Answer Correct ?    22 Yes 4 No

main() { int i; clrscr(); for(i=0;i<5;i++) { printf("%d\..

Answer / karthi

b.o,1,2,3,4

Is This Answer Correct ?    0 Yes 9 No

main() { int i; clrscr(); for(i=0;i<5;i++) { printf("%d\..

Answer / aditi

none of them is correct...

coz l does'nt make any diff...

and << means a left shift

o in binary is 0 only...
and wen it is lft shfted it remains same...
1 in binary is 01 >> makes it 010 i.e 2
nd so on...

Is This Answer Correct ?    1 Yes 15 No

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