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main()

{

char a[4]="HELLO";

printf("%s",a);

}

Answers were Sorted based on User's Feedback



main() { char a[4]="HELLO"; printf("%s",a); ..

Answer / dani

Actually I compiled this and ran it unix and it just prints out a warning, not an error:
"warning: initializer-string for array of chars is too long"

The programme prints the initial array without the last character (because of the '\0' special character):
"HELL &#65533;"

Is This Answer Correct ?    5 Yes 1 No

main() { char a[4]="HELLO"; printf("%s",a); ..

Answer / smk

too many intializer for a[4](warning)

Is This Answer Correct ?    3 Yes 0 No

main() { char a[4]="HELLO"; printf("%s",a); ..

Answer / susie

Answer :

Compiler error: Too many initializers

Explanation:

The array a is of size 4 but the string constant requires 6
bytes to get stored.

Is This Answer Correct ?    2 Yes 2 No

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