Answer / muni

I am sorry the previous answer is for different question.

For your question the answer is ver simple.

use sprintf and strlen.

char str[10];
sprintf(str,"%d",number)
number of digits = strlen(str);

Answer / ramesh

int countDigits(number)
{
if (number==0)
return 0;
else
return 1 + countDigits(number%10);

}

Answer / devendra

Answer #2 is right we can also use atoi() and itoa() function.

Answer / arti sharma

void main()
{ int num,i,count=0;
printf("enter a no");
scanf("%d",&num);
while(num!=0)
{ count=count+1;
i=num%10;
num=num/10;
}
printf("count=%d",count);
getch();
}

Answer / sreejesh1987

Small change to Ramesh's answer.
I got answer when i done like this.

int countDigits(number)
{
if (number==0)
return 0;
else
return 1 + countDigits(number/10);//change % to /

}

Answer / muni

There is no function to calculate the number of bits. But
there is a very simple logic for calculating it.

int count = 0;

While( num!=0 )
{
count++;
num = num & (num-1);
}

void main() { unsigned giveit=-1; int gotit; printf("%u ",++giveit); printf("%u \n",gotit=--giveit); }

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