Answer / raghuram.a

#include<stdio.h>
long pow(long a,long b) /*finds a power of b*/
{
long i,j=1;
for(i=1;i<=b;i++)
j*=a;
return j;
}
long bin(int n) /*converts into binary equivalent */
{
long i=0,j=1,r;
while(n)
{
r=n%2;
i=i+r*j;
n/=2;
j*=10;
}
return i;
}
main()
{
char a[25];
long i,j,k,m,l=0,n=0;
printf("\nEnter string:");
scanf("%s",a);
printf("\nAll possible substrings are:\n");
while(a[l])
l++;
printf("%d)\t{ }\n",++n);
for(i=1;i<pow(2,l);i++)
{ k=bin(i);
m=l-1;
printf("%d)\t{ ",++n);
while(m>=0)
{
j=k/pow(10,m);
if(j==1)
printf("%c",a[l-1-m]);

k=k%pow(10,m);
m--;
}
printf("\t}\n");
}
return 0;
}

Answer / raghuram.a

#include<stdio.h>
#include<conio.h>
long pow(long a,long b) /*finds a power of b*/
{
long i,j=1;
for(i=1;i<=b;i++)
j*=a;
return j;
}
long bin(int n) /*converts into binary equivalent */
{
long i=0,j=1,r;
while(n)
{
r=n%2;
i=i+r*j;
n/=2;
j*=10;
}
return i;
}
main()
{
char a[25];
long i,j,k,m,l=0,n=0;
printf("\nEnter string:");
scanf("%s",a);
printf("\nAll possible substrings are:\n");
while(a[l])
l++;
printf("%d)\t{ }\n",++n);
for(i=1;i<pow(2,l);i++)
{ k=bin(i);
m=l-1;
printf("%d)\t{ ",++n);
while(m>=0)
{
j=k/pow(10,m);
if(j==1)
printf("%c",a[l-1-m]);

k=k%pow(10,m);
m--;
}
printf("\t}\n");
}
getch();
return 0;
}

Answer / gordon roberts

Here is a trivial Java function to do this. At least two
of the above answers do not work at all...??? The binary
solution seems to have some merit but why make it so
difficult and problem frought??? I put in an element
counter to verify the correct number of elements in the set
upon print out. Call the function below using the obvious
form:

printSubsets("", "abc");

static int m_cElements = 1;
private static void printSubsets(String prefix, String str)
{
if(str.equals(""))
System.out.println((m_cElements++)+": {"+prefix+"}");
else
{
printSubsets(prefix, str.substring(1));
printSubsets(prefix+str.substring(0,1), str.substring
(1));
}
}

Answer / suchitpuri

i have written a program in java which print all the subsets
i am using binary representation to calculate the subset
ie 100 means a
101 means ac
111 abc and so on


/*
* To change this template, choose Tools | Templates
* and open the template in the editor.
*/

/**
*
* @author spuri
*/
public class printSubsets
{

static char input[] = { 'a', 'b', 'c' };

/**
* @param args
* the command line arguments
*/
public static void main(String[] args)
{
// TODO code application logic here


Integer i = new Integer((int) Math.pow(2, input.length));

for (int k = 0; k < i; k++)
{
if (k == 0)
{
System.out.print("{}");
}
else
{
String temp = new String();
char op[] = Integer.toBinaryString(k).toCharArray();
if (op.length <= input.length)
{
for (int j = 0; j < (input.length - op.length); j++)
{
temp = temp + "0";
}
}
temp = temp + new String(op);
printSequence(temp.toCharArray());

}

}

}

public static void printSequence(char[] op)
{

System.out.print("{");

for (int i = 0; i < op.length; i++)
{

if (op[i] == '1')
{
System.out.print(input[i]);

}
}
System.out.print("}");

}
}

Answer / a

aa

Answer / shashanktrip

int combine(char in[])
{

int len;
char *out;
len= strlen(in);
printf("<<<<<<<<Combinations>>>>>>");
out=(char *)malloc(sizeof(char)*(len+1));
if(!out)return -1;

DoCombine(in,out,len,0,0);
free(out);
return 1;
}


void DoCombine(char *in, char *out, int len, int
recLevel,int start)
{
int i;
for(i=start;i<len;i++)
{
out[recLevel]=in[i];
out[recLevel+1]='\0';
printf("\n%s\n",out);
if(i<len-1)

DoCombine(in,out,len,recLevel+1,i+1);
}
}

Answer / vadivel

# include<stdio.h>
# include<conio.h>
# include<alloc.h>
# include<string.h>
# include<math.h>

int bin[16];
void genbin(int);

void main()
{
clrscr();
char *str;
int i=0,len=0;
str = (char*)malloc(100);
printf("Input a no. :");
scanf("%s",str);
len = pow(2,strlen(str));
for(i=0;i < len;i++)
{
genbin(i);
for(int j=0;j < strlen(str);j++)
{
if(bin[j] == 1)
printf("%c",str[j]);
}
printf("\n");
}
free(str);
getch();
}
void genbin(int n)
{
for(int i=0;i<8;i++)
{
bin[i] = n%2;
n /= 2;
}
}

Answer / nkbinglei

#include <iostream>
#include <string>
using namespace std;
#include<math.h>

int main(int argc, char* argv[])
{
char input[100];

cout<<"input a string:"<<endl;
gets(input);
cout<<input<<endl;
int strLen = strlen(input);
int count = pow(2.0,strLen);
string *str = new string[count];
int num=0;
cout<<"{}"<<endl;
for(int i=0;i<strLen;i++)
{
str[num] = str[num]+input[i];
cout<<"{"<<str[num]<<"}"<<endl;
num++;
for(int j=0;j<i;j++)
{
str[num] = str[j]+','+input[i];
cout<<"{"<<str[num]<<"}"<<endl;
num++;
}
}

}

Answer / vijay nag

find the no of bits required to represent the value n.i.e.
no of elements in the set.This can be done using following
algorithm.
int bin(int n)
{
if(n==1)return 1;
return 1_n/2_1+1;
}
print(char c[12],int b)
{
for(int i=0;i<b;i++)
if(c[i]=='1')
printf("%c",65+i);
}

combinations(int n)
{
int b=bin(n);
char c[12];
for(int i=0;i<pow(2,b);i++)
{
for(int j=1;j<b;j++)
if(i>>1)
c[j-1]='1';
else
c[j-1]='0';

print(c,b);
}

Answer / lakshmeeprasad

#include<stdio.h>
#include<string.h>
void main()
{
char str[10];
int len=0,i,j,k;
printf("Enter String......: ");
scanf("%[^\n]",str);
printf("\n\nEntered String is......: ");
puts(str);
len = strlen(str);
printf("\nlength=%d\n",len);
for(i=0 ; i<len ; i++)
{
for(j=i ; j<len ; j++)
{
for(k=i ; k<=j ; k++)
printf("%c",str[k]);
printf("\n");
}
printf("\n");
}
}

main() { int k=1; printf("%d==1 is ""%s",k,k==1?"TRUE":"FALSE"); }

1 Answers  

#include<stdio.h> main() { const int i=4; float j; j = ++i; printf("%d %f", i,++j); }

1 Answers  

main() { int i=5; printf("%d%d%d%d%d%d",i++,i--,++i,--i,i); }

7 Answers  

main() { char *p="GOOD"; char a[ ]="GOOD"; printf("\n sizeof(p) = %d, sizeof(*p) = %d, strlen(p) = %d", sizeof(p), sizeof(*p), strlen(p)); printf("\n sizeof(a) = %d, strlen(a) = %d", sizeof(a), strlen(a)); }

1 Answers  

What is the main difference between STRUCTURE and UNION?

13 Answers   HCL,

main() { show(); } void show() { printf("I'm the greatest"); }

2 Answers  

Write a routine that prints out a 2-D array in spiral order

3 Answers   Microsoft,

#define a 10 void foo() { #undef a #define a 50 } int main() { printf("%d..",a); foo(); printf("%d..",a); return 0; } explain the answer

1 Answers  

#include<stdio.h> int main() { int x=2,y; y=++x*x++*++x; printf("%d",y); } Output for this program is 64. can you explain how this output is come??

1 Answers  

print numbers till we want without using loops or condition statements like specifically(for,do while, while swiches, if etc)!

11 Answers   Wipro,

Write a program to check whether the number is prime and also check if it there i n fibonacci series, then return true otherwise return false

1 Answers   Cognizant, lenovo,

Write a program that reads a dynamic array of 40 integers and displays only even integers

2 Answers