Answer / naresh thakur

500 no. of bricks(brick size - 20cm.*10cm.*10cm.) required
for 1 cum of brick masonry.

and suppose, ratio = 1:6
then , sum = 1+6 = 7
as we know, total dry mortar required for 1 cum. of brick
masonry = 0.30 cum.

therefore following dry matrial required.

cement = 1* 0.30/7 = .04 cum. *28.8 = 1.15 bags.

sand = 6* 0.30/7 = 0.26 cum.
or 0.26 cum. * 35.3 = 9.18 cft.


Material required for 1 cum. of brick masonry in mortar
ratio of 1:6.

cement = 1.15 bags.
sand = 9.18 cft.
bricks = 500 nos.

Answer / tarun

500

Answer / aamir mushtaq shah

496 Bricks of nominal size 9"x4"x3" are required in 1 cum in
1:6 mortor

Answer / mahendra mohan srivastava

Mr naresh is given right answer based on standard brick
20.10.10
but we are using in construction 23.11.7 then we cuse 520
brick.

Answer / shanmugam

theroritically it is 500, but practically it is 490 bricks required for 1 cu-m,
when you go feet and inches for 1 cft it is around 14.5 nos

Answer / bhavya

can u tell me how this practical and theoritical value is different???

Answer / akbar_u2u

how many men days of loburs and masons are requirete for 1
cum,pcc (1:2:4),Pcc(1:3:6) and Pcc(1:4:8)
thanking you

Answer / farhat abbas naqvi

As thickness of motar is not uniform it should be

taken as 32% instead of 30%.To level the top masons

usually use motar more than 1cm as it should be.

Answer / abdur rahman

1cm=35.32 cft
normal size of brick=.75*.375*.25=.0703
if volum 35.32cft
morter.30%
morter=35.32*.30=10.59
brick=35.32-10.59=24.724/.0703=351bricks
ratio 1;6=7
1/7*10.59*1.27/1.25=1.54 cement
6/7*10.59*1.27=11.52 cft sand

Answer / sobhanbabu

theritically 500 bricks and practically 450 to 480.here
practically means type of skilled mason and labor.it needs
58 kg cement to construct a cumec of brick work of size
19*9*9cm

how to calculate weight of 1.8 cum of aggregate

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