Answer / y_suhas

you must know the current density then you find relation
between current & area

d=I/A,
d-current density
I- Current
A-conductor area in sq mm

Answer / premnath

c = l/(r*a)
c = electrical conductivity
l = length of wire
r = resistance of wire
a = cross sectional area of wire

Answer / k.a.sharma

Current carrying capacity is given by

I = (V*a)/(r*l)

I = Current carrying capacity
V = Max. allowable voltage drop in length 'l' by design.
a = cross sectional area of wire
r = specific resistance of material of wire
l = length of wire

Answer / vinod

a=i/d

a=crosssectional area
i= current
d=current density

Answer / víctor

As a thumbrule for home applications you can count 6 amp
per sq mm.
Large currents needs to take a look at the conductor
manufacturer.

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