Answer / reshi

If we assume the power factor during motor running as 0.85.
Then the calculation will be 40MW/0.85= 47MVA.Answer.

Answer / riyadh

this formula u going to apply

Kw=Kva*P.f

we know P.f = 0.9 for T/f's
P.f = 0.8 for Generator

we knw power kw 40Mw

Apply to above formula Kva = kw / p.f
Kva = 40000 Kw / 0.8
Kva = 50000 kva
In Mva is 50

Answer / chethan

p- 40MW,v,220volts kva=?

40*1000000*4.54Amps multiply (1000=1.732*220*I,ans.4.54)
Ans. 181600 KVA

this is my knoldge ,so this is error,please tell me the
correct answer.

Answer / malkit singh

Its 50000Kva on .8 pf and answer#3 is correct.

Answer / jayaraj

The question is wrong. 40MW load could not be fed from 220v 3 ph system. If the question is the KVA requirement 50000KVA on .8 pf. So in a distribution system 2000KVA Transformer 25 nos are required.

Answer / mohit

660 MV.

Answer / v.s.narayanaswami

THE ABOVE FORMLA APPLIES FOR CONVERSION OF HP INTO KVA AND
THE CORRECT CONVERSION FACTOR IS 0.764.

THE REQUIREMENTS OF 40 HP CONNECTION CONVERTED INTO KVA
APPLYING THE FORMULA IE 1 HP = 0.764 KVA IS 40HP/0.764 IS
APPROXIMATELY IS 52 KVA.

HENCE UR CORRECT REPLY IS SOLICITED FOR ARRIVING AT THE KVA
DEMAND FOR THE ESTIMATED 40 MW OF POWER CONNECTION
REGARDS

V.S.NARAYANASWAMI
B.COM(HONS), M.COM, F.C.A

Hi, I'm running plastic reprocessing company where all motors are running only in delta. Due to that when I use start my 30 hp motor my transformer gets fuse. Where it happens two times a day. I gt a suggestion from a person about Automatic Power Factor Controller APFC. Is it useful for my problem??? Or is der any other way for solving this problem?? Upgrading the transformer is difficult. Pls give Me ur suggestion. Waiting for ur reply.

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