why java is platform independent?
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Answer / dinesh haridoss
Java was designed to not only be cross-platform in source
form like C, but also in compiled binary form. Since this
is frankly impossible across processor architectures Java
is compiled to an intermediate form called byte-code. A
Java program never really executes natively on the host
machine. Rather a special native program called the Java
interpreter reads the byte code and executes the
corresponding native machine instructions. Thus to port
Java programs to a new platform all that is needed is to
port the interpreter and some of the library routines. Even
the compiler is written in Java. The byte codes are
precisely defined, and remain the same on all platforms.
The second important part of making Java cross-platform is
the elimination of undefined or architecture dependent
constructs. Integers are always four bytes long, and
floating point variables follow the IEEE 754 standard for
computer arithmetic exactly. You don't have to worry that
the meaning of an integer is going to change if you move
from a Pentium to a PowerPC. In Java everything is
guaranteed.
| Is This Answer Correct ? | 4 Yes | 7 No |
Answer / asha
java have java virtual machine which make java plateform
independent..jvm convert input source code into bye code
which is run on any plateform..
| Is This Answer Correct ? | 9 Yes | 13 No |
Answer / suresh
java is platform independent because the virtual machine
include all operating system,so java is run on any platform
java compiler converted source code into byte code,then the
jvm to translate the byte code into machine code
| Is This Answer Correct ? | 3 Yes | 7 No |
In the following pgm add a stmt in the function fun such that the address of 'a' gets stored in 'j'. main(){ int * j; void fun(int **); fun(&j); } void fun(int **k) { int a =0; /* add a stmt here*/ }
Which one is taking more time and why ? :/home/amaresh/Testing# cat time.c //#include <stdio.h> #define EOF -1 int main() { register int c; while ((c = getchar()) != EOF) { putchar(c); } return 0; } ------------------- WIth stdio.h:- :/home/amaresh/Testing# time ./time_header hi hi hru? hru? real 0 m4.202s user 0 m0.000s sys 0 m0.004s ------------------ Witout stdio.h and with #define EOF -1 =================== /home/amaresh/Testing# time ./time_EOF hi hi hru? hru? real 0 m4.805s user 0 m0.004s sys 0 m0.004s -- From above two case , why 2nd case is taking more time ?
main() { char a[4]="HELLO"; printf("%s",a); }
Print an integer using only putchar. Try doing it without using extra storage.
Write a program that reads a dynamic array of 40 integers and displays only even integers
main() { char str1[] = {‘s’,’o’,’m’,’e’}; char str2[] = {‘s’,’o’,’m’,’e’,’\0’}; while (strcmp(str1,str2)) printf(“Strings are not equal\n”); }
/*what is the output for*/ void main() { int r; printf("Naveen"); r=printf(); getch(); }
write a program in c to merge two array
write a program for area of circumference of shapes
main() { char not; not=!2; printf("%d",not); }
What is data _null_? ,Explain with code when u need to use it in data step programming ?
#define a 10 int main() { printf("%d..",a); foo(); printf("%d..",a); return 0; } void foo() { #undef a #define a 50 }