Answer / raghuram

void putlong(unsigned long x)
{ if (x > 10) putlong(x / 10);
putchar(x % 10+'0');
}
main()
{
long int a;
printf("enter long integer:");
scanf("%d",&a);
putlong(a);
return 0;

}

Answer / cmos

This can be done by recursion.
Since the number of recursive calls is not significant, it does not affect the performance much

printnumber(int i)
{
if(i == 0)
return;
printnumber(i/10);
putchar(’0′ + i%10);
}

can u give me the c codings for converting a string into the hexa decimal form......

1 Answers  

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main ( ) { static char *s[ ] = {“black”, “white”, “yellow”, “violet”}; char **ptr[ ] = {s+3, s+2, s+1, s}, ***p; p = ptr; **++p; printf(“%s”,*--*++p + 3); }

1 Answers  

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main() { int i=0; for(;i++;printf("%d",i)) ; printf("%d",i); }

1 Answers   Zoho,

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#include<stdio.h> main() { int a[2][2][2] = { {10,2,3,4}, {5,6,7,8} }; int *p,*q; p=&a[2][2][2]; *q=***a; printf("%d----%d",*p,*q); }

1 Answers  

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write the function. if all the character in string B appear in string A, return true, otherwise return false.

11 Answers   Google,

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abcdedcba abc cba ab ba a a

2 Answers  

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main( ) { char *q; int j; for (j=0; j<3; j++) scanf(“%s” ,(q+j)); for (j=0; j<3; j++) printf(“%c” ,*(q+j)); for (j=0; j<3; j++) printf(“%s” ,(q+j)); }

1 Answers  

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int i=10; main() { extern int i; { int i=20; { const volatile unsigned i=30; printf("%d",i); } printf("%d",i); } printf("%d",i); }

1 Answers  

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print numbers till we want without using loops or condition statements like specifically(for,do while, while swiches, if etc)!

11 Answers   Wipro,

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Write a C program to print ‘Campus Force training’ without using even a single semicolon in the program.

3 Answers   Wipro,

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#include<conio.h> main() { int x,y=2,z,a; if(x=y%2) z=2; a=2; printf("%d %d ",z,x); }

1 Answers  

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main( ) { int a[ ] = {10,20,30,40,50},j,*p; for(j=0; j<5; j++) { printf(“%d” ,*a); a++; } p = a; for(j=0; j<5; j++) { printf(“%d ” ,*p); p++; } }

1 Answers  

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