Answer / susie

Answer :

mmmm

aaaa

nnnn

Explanation:

s[i], *(i+s), *(s+i), i[s] are all different
ways of expressing the same idea. Generally array name is
the base address for that array. Here s is the base address.
i is the index number/displacement from the base address.
So, indirecting it with * is same as s[i]. i[s] may be
surprising. But in the case of C it is same as s[i].

main() { int a[10]; printf("%d",*a+1-*a+3); }

1 Answers  

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can you use proc sql to manpulate a data set or would u prefer to use proc report ? if so why ? make up an example and explain in detail

0 Answers   TCS,

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In a gymnastic competition, scoring is based on the average of all scores given by the judges excluding the maximum and minimum scores. Let the user input the number of judges, after that, input the scores from the judges. Output the average score. Note: In case, more than two judges give the same score and it happens that score is the maximum or minimum then just eliminate two scores. For example, if the number of judges is 5 and all of them give 10 points each. Then the maximum and minimum score is 10. So the computation would be 10+10+10, this time. The output should be 10 because 30/3 is 10.

0 Answers   TCS,

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main(){ char a[100]; a[0]='a';a[1]]='b';a[2]='c';a[4]='d'; abc(a); } abc(char a[]){ a++; printf("%c",*a); a++; printf("%c",*a); }

2 Answers  

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To Write a C program to remove the repeated characters in the entered expression or in entered characters(i.e) removing duplicates.

19 Answers   Amazon, BITS, Microsoft, Syncfusion, Synergy, Vector,

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const int perplexed = 2; #define perplexed 3 main() { #ifdef perplexed #undef perplexed #define perplexed 4 #endif printf("%d",perplexed); } a. 0 b. 2 c. 4 d. none of the above

1 Answers   emc2, HCL,

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main() { int i=10; i=!i>14; Printf ("i=%d",i); }

1 Answers  

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union u { union u { int i; int j; }a[10]; int b[10]; }u; main() { printf("\n%d", sizeof(u)); printf(" %d", sizeof(u.a)); // printf("%d", sizeof(u.a[4].i)); } a. 4, 4, 4 b. 40, 4, 4 c. 1, 100, 1 d. 40 400 4

3 Answers   HCL,

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abcdedcba abc cba ab ba a a

2 Answers  

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main() { void swap(); int x=10,y=8; swap(&x,&y); printf("x=%d y=%d",x,y); } void swap(int *a, int *b) { *a ^= *b, *b ^= *a, *a ^= *b; }

2 Answers  

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struct Foo { char *pName; char *pAddress; }; main() { struct Foo *obj = malloc(sizeof(struct Foo)); clrscr(); obj->pName = malloc(100); obj->pAddress = malloc(100); strcpy(obj->pName,"Your Name"); strcpy(obj->pAddress, "Your Address"); free(obj); printf("%s", obj->pName); printf("%s", obj->pAddress); } a. Your Name, Your Address b. Your Address, Your Address c. Your Name Your Name d. None of the above

2 Answers   HCL,

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Write out a function that prints out all the permutations of a string. For example, abc would give you abc, acb, bac, bca, cab, cba. You can assume that all the characters will be unique.

5 Answers   IITR, Microsoft, Nike,

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