Finding a number multiplication of 8 with out using arithmetic operator

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Finding a number multiplication of 8 with out using
arithmetic operator

Question Posted / guest

8 Answers
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Finding a number multiplication of 8 with out using arithmetic operator..

Answer / wl

i << 3

Is This Answer Correct ?

9 Yes

2 No

Finding a number multiplication of 8 with out using arithmetic operator..

Answer / splurgeop

/* PROGRAM TO FIND WHETHER A NUMBER IS A MULTIPLE OF 2
AND 8 WITHOUT
USING ARITHMETIC OPERATOR */

#include<stdio.h>
#include<conio.h>
void main()
{
int num;
clrscr();
printf("\n enter a number");
scanf("%d",&num);
if(num & 1)
printf("\n not a multiple of 2");
else
printf("\n a multiple of 2");
if(num & 7)
printf("\n not a multiple of 8");
else
printf("\n a multiple of 8");

getch();
}

Is This Answer Correct ?

6 Yes

1 No

Finding a number multiplication of 8 with out using arithmetic operator..

Answer / raghuram.a

i=n<<3;

Is This Answer Correct ?

2 Yes

0 No

Finding a number multiplication of 8 with out using arithmetic operator..

Answer / lloyd.tumulak

boolean div8(x){
return (x & 7)
}

if return is 0 = divisible by 8

Is This Answer Correct ?

3 Yes

1 No

Finding a number multiplication of 8 with out using arithmetic operator..

Answer / ram

int i,n=1;
i=n<<3

Is This Answer Correct ?

3 Yes

1 No

Finding a number multiplication of 8 with out using arithmetic operator..

Answer / saravanan e

#include <stdio.h>
main()
{
int x,n;
printf("Enter the X number:");
scanf("%d",&x);
n=(x<<3)-x;
printf("The Answer is : %d",n);
getch();
}

Is This Answer Correct ?

2 Yes

2 No

Finding a number multiplication of 8 with out using arithmetic operator..

Answer / saravanan e , ps technologies,

#include <stdio.h>
main()
{
int x,n;
printf("Enter the X number:");
scanf("%d",&x);
n=(x<<3)-x;
printf("The Answer is : %d",n);
getch();
}

Is This Answer Correct ?

1 Yes

3 No

Finding a number multiplication of 8 with out using arithmetic operator..

Answer / aditya raj

#include<stdio.h>
main()
{
int n;
scanf("%d",&n);
if((n&7)==0) printf("yes\n");
else printf("no\n");
}

Is This Answer Correct ?

0 Yes

2 No

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