Finding a number multiplication of 8 with out using
arithmetic operator
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Answer / splurgeop
/* PROGRAM TO FIND WHETHER A NUMBER IS A MULTIPLE OF 2
AND 8 WITHOUT
USING ARITHMETIC OPERATOR */
#include<stdio.h>
#include<conio.h>
void main()
{
int num;
clrscr();
printf("\n enter a number");
scanf("%d",&num);
if(num & 1)
printf("\n not a multiple of 2");
else
printf("\n a multiple of 2");
if(num & 7)
printf("\n not a multiple of 8");
else
printf("\n a multiple of 8");
getch();
}
| Is This Answer Correct ? | 6 Yes | 1 No |
Answer / lloyd.tumulak
boolean div8(x){
return (x & 7)
}
if return is 0 = divisible by 8
| Is This Answer Correct ? | 3 Yes | 1 No |
Answer / saravanan e
#include <stdio.h>
main()
{
int x,n;
printf("Enter the X number:");
scanf("%d",&x);
n=(x<<3)-x;
printf("The Answer is : %d",n);
getch();
}
| Is This Answer Correct ? | 2 Yes | 2 No |
Answer / saravanan e , ps technologies,
#include <stdio.h>
main()
{
int x,n;
printf("Enter the X number:");
scanf("%d",&x);
n=(x<<3)-x;
printf("The Answer is : %d",n);
getch();
}
| Is This Answer Correct ? | 1 Yes | 3 No |
Answer / aditya raj
#include<stdio.h>
main()
{
int n;
scanf("%d",&n);
if((n&7)==0) printf("yes\n");
else printf("no\n");
}
| Is This Answer Correct ? | 0 Yes | 2 No |
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C Code 
