void main()
{
char a[]="12345\0";
int i=strlen(a);
printf("here in 3 %d\n",++i);
}
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Answer / susie
Answer :
here in 3 6
Explanation:
The char array 'a' will hold the initialized string, whose
length will be counted from 0 till the null character. Hence
the 'I' will hold the value equal to 5, after the
pre-increment in the printf statement, the 6 will be printed.
| Is This Answer Correct ? | 18 Yes | 4 No |
Answer / ravneet kaur
as this is a character array and would have string in double
quotes so this code shows an error i.e. *char wont changes
to *int.
| Is This Answer Correct ? | 0 Yes | 5 No |
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C Code 
