void main()
{
char a[]="12345\0";
int i=strlen(a);
printf("here in 3 %d\n",++i);
}
Answers were Sorted based on User's Feedback
Answer / susie
Answer :
here in 3 6
Explanation:
The char array 'a' will hold the initialized string, whose
length will be counted from 0 till the null character. Hence
the 'I' will hold the value equal to 5, after the
pre-increment in the printf statement, the 6 will be printed.
| Is This Answer Correct ? | 18 Yes | 4 No |
Answer / ravneet kaur
as this is a character array and would have string in double
quotes so this code shows an error i.e. *char wont changes
to *int.
| Is This Answer Correct ? | 0 Yes | 5 No |
What are segment and offset addresses?
int swap(int *a,int *b) { *a=*a+*b;*b=*a-*b;*a=*a-*b; } main() { int x=10,y=20; swap(&x,&y); printf("x= %d y = %d\n",x,y); }
3) Int Matrix of certain size was given, We had few valu= es in it like this. =97=97=97=97=97=97=97=97=97=97=97 1 = | 4 | | 5 | &= nbsp; | 45 =97=97=97=97=97=97=97=97=97=97=97 &n= bsp; | 3 | 3 | 5 | = | 4 =97=97=97=97=97=97=97=97=97=97=97 34 |&nbs= p; 3 | 3 | | 12 | &= nbsp; =97=97=97=97=97=97=97=97=97=97=97 3 | &nbs= p; | 3 | 4 | = | 3 =97=97=97=97=97=97=97=97=97=97=97 3 | = ; | | | = ; 3 | =97=97=97=97=97=97=97=97=97=97=97 &= nbsp; | | 4 | = ; | 4 | 3 We w= ere supposed to move back all the spaces in it at the end. Note: = If implemented this prog using recursion, would get higher preference.
#include <stdio.h> #define a 10 main() { #define a 50 printf("%d",a); }
main() { int i=5; printf(ā%dā,i=++i ==6); }
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