Answer / susie

Answer :

here in 3 6

Explanation:

The char array 'a' will hold the initialized string, whose
length will be counted from 0 till the null character. Hence
the 'I' will hold the value equal to 5, after the
pre-increment in the printf statement, the 6 will be printed.

Answer / lucky varshney

here in 3
7

Answer / ravneet kaur

as this is a character array and would have string in double
quotes so this code shows an error i.e. *char wont changes
to *int.

main() { int i, j; scanf("%d %d"+scanf("%d %d", &i, &j)); printf("%d %d", i, j); } a. Runtime error. b. 0, 0 c. Compile error d. the first two values entered by the user

2 Answers   HCL,

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main() { int a=10,*j; void *k; j=k=&a; j++; k++; printf("\n %u %u ",j,k); }

1 Answers  

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what will be the output of this program? void main() { int a[]={5,10,15}; int i=0,num; num=a[++i] + ++i +(++i); printf("%d",num); }

3 Answers   Wipro,

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Develop a routine to reflect an object about an arbitrarily selected plane

0 Answers  

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main( ) { char *q; int j; for (j=0; j<3; j++) scanf(“%s” ,(q+j)); for (j=0; j<3; j++) printf(“%c” ,*(q+j)); for (j=0; j<3; j++) printf(“%s” ,(q+j)); }

1 Answers  

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struct aaa{ struct aaa *prev; int i; struct aaa *next; }; main() { struct aaa abc,def,ghi,jkl; int x=100; abc.i=0;abc.prev=&jkl; abc.next=&def; def.i=1;def.prev=&abc;def.next=&ghi; ghi.i=2;ghi.prev=&def; ghi.next=&jkl; jkl.i=3;jkl.prev=&ghi;jkl.next=&abc; x=abc.next->next->prev->next->i; printf("%d",x); }

1 Answers  

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what is the output of following program ? void main() { int i=5; printf("%d %d %d %d %d ",i++,i--,++i,--i,i); }

10 Answers  

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void main() { int i=5; printf("%d",i+++++i); }

3 Answers  

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program to Reverse a linked list

12 Answers   Aricent, Microsoft, Ness Technologies,

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main() { int i=10; i=!i>14; Printf ("i=%d",i); }

1 Answers  

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main() { int i = 3; for (;i++=0;) printf(“%d”,i); }

1 Answers   CSC,

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What are segment and offset addresses?

2 Answers   Infosys,

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