Question 55 - The differential equation is 3 dy / dt + 2y = 1 with y(0) = 1. (a

Question 55 - The differential equation is 3 dy / dt + 2y = 1 with y(0) = 1. (a) The Laplace transformation, L for given terms are : L (dy / dt) = sY(s) - y(0), L(y) = Y(s), L(1) = 1 / s. Use such transformation to find Y(s). (b) The initial value theorem states that : When t approaches 0 for a function of y(t), it is equal to a function of sY(s) when s approaches infinity. Use the initial value theorem as a check to the answer found in part (a).

Question Posted / kang chuen tat (malaysia - pen

1 Answers
2449 Views
I also Faced
E-Mail Answers

Question 55 - The differential equation is 3 dy / dt + 2y = 1 with y(0) = 1. (a) The Laplace transf..

Answer / kang chuen tat (malaysia - pen

Answer 55 - (a) For the equation 3 dy / dt + 2y = 1, its Laplace transformation is 3 [ sY(s) - y(0) ] + 2Y(s) = 1 / s, 3 (sY - 1) + 2Y = 1 / s, 3sY - 3 + 2Y = 1 / s, 3sY + 2Y = 1 / s + 3, Y (3s + 2) = (1 + 3s) / s. Y = Y(s) = (1 + 3s) / [ s (3s + 2) ]. (b) Initial value theorem states that y(0) = sY(infinity), then 1 = s (1 + 3s) / [ s (3s + 2) ] = (1 + 3s) / (3s + 2) approaches 1 when the value of s approaches infinity. The checking is correct. The answer is given by Kang Chuen Tat; PO Box 6263, Dandenong, Victoria VIC 3175, Australia; SMS +61405421706; chuentat@hotmail.com; http://kangchuentat.wordpress.com.

Is This Answer Correct ?

1 Yes

0 No

Post New Answer

More Chemical Engineering Interview Questions

What are some characteristics of bulk solids that can affect their ability to flow properly?

0 Answers

ENVIRONMENTAL ENGINEERING - QUESTION 22.2 : Biochemical Oxygen Demand (BOD) could be calculated using the formula BOD = (DOi - DOf) (Vb / Vs) where Vb = Volume of bottle in ml, Vs = Volume of sample in ml, DOi = Initial dissolved oxygen in mg / L, DOf = Final dissolved oxygen in mg / L. (a) By using a bottle of Vb = 300 ml with sample Vs = 30 ml, find the BOD if DOi = 8.8 mg / L and DOf = 5.9 mg / L. (b) By using a bottle Vb = 600 mL with sample Vs = 100 mL, find the BOD if DOi = 8.8 mg / L and DOf = 4.2 mg / L. (c) Find the average BOD = [ Answer of (a) + Answer of (b) ] / 2. (d) If the BOD-5 test for (a) - (c) is run on a secondary effluent using a nitrification inhibitor, find the nitrogenous BOD (NBOD) = TBOD - CBOD. Let TBOD = 45 mg / L and CBOD = Answer of (c).

1 Answers

What is the meaning of the critical speed of a turbine, and what are its effects on the shaft line

1 Answers

who is the first atomic scientist in india?

5 Answers IGCAR,

How to calculate the sonic velocity of a gas stream?

1 Answers Sony,

motor vs pump

1 Answers Inogent Laboratories,

hi.i m student of chemical engg. and studying in 5 th sem.how can i improve my technical knowledge..can u sugest me a link like book or any website..?

3 Answers

A shiny brown colored element ‘x’ on heating in air becomes black in cooler name the element ‘x’and black colored compound formed?

0 Answers

What is higher heating value and lower heating value? Is it positive or negative?

0 Answers

an anybody provide me the HPCL apptitude papers?am having the test on this feb 27th 2008 so plz [Send This Question to Your Friend] please send me hpcl placement papers both technical and apptitude.. please

3 Answers HPCL, NTPC,

Explain the reasons of removal of particles from effluent gas?

0 Answers

1 Answers

For more Chemical Engineering Interview Questions Click Here