Answer / kang chuen tat

One kilogram has 2.2046 pounds, 1 metre has 3.2808 feet and 1 metre has 39.37 inches. The answer is given by Kang Chuen Tat; PO Box 6263, Dandenong, Victoria VIC 3175, Australia; SMS +61405421706; chuentat@hotmail.com; http://kangchuentat.wordpress.com.

What are the types of load?

0 Answers  

---

ACCOUNTING AND FINANCIAL ENGINEERING - EXAMPLE 34.25 : (a) If an engineering company has a policy to maintain A % debt ratio, it will limit its total debt B, to A % of all company assets with total assets C. Find the value of A as a function of B and C. (b) An engineering consultancy that designs biochemical processing plants has a beginning balance in a bank of value D. The interest paid by the bank to the consultancy for the saving is E. The consultancy withdraws F amount of money from the bank to cover the project cost. (i) Calculate the end balance in a bank of the consultancy by using the symbols of D, E and F etc. (ii) Find the value of the principal due to E and F.

1 Answers  

---

Explain the working of a spray condenser?

0 Answers  

---

Define a surfactant?

0 Answers  

---

what is the difference between the heat exchanger and cooling tower???????????

10 Answers   BARC, Essar,

---

---

What is the maximum recommended velocity for steam in a plant pipe network?

0 Answers  

---

What is the most common cause of solid size segregation in bulk solid systems?

0 Answers   TATA,

---

whats the allowed tolerance of pipe to pipe butt joint mismatching

0 Answers  

---

What happens when fuel is burned , what are compounds released??

3 Answers   Reddy Labs,

---

what is mean by reflux ratio?

4 Answers  

---

Explain what are some good uses of low-grade steam at 12 atm and 1920c?

0 Answers  

---

Question 33 – By using Excel program either on laptop or desktop PC, solve the differential equation dy / dx = -2y + x + 4 with h = 0.005, initial values : x = 0, y = 1. The 4th order Runge-Kutta method provides : y(N + 1) = y(N) + (1/6) (k1 + 2k2 +2k3 + k4), k1 = h [ -2y(N) + x(N) + 4 ], k2 = h { -2 [ y(N) + k1 / 2 ] + x(N) + h / 2 + 4 }, k3 = h { -2 [ y(N) + k2 / 2 ] + x(N) + h / 2 + 4 }, k4 = h { -2 [ y(N) + k3 ] + x(N) + h + 4 }. What is the value of y at x = 0.5?

1 Answers  

---