Answer / kangchuentat

CHEMICAL ENERGY BALANCE - ANSWER 11.5 : Let x(1) = x(2) = 0.5 for 50 : 50 mole fraction mixture, then P = x(1) p(1) g(1) + x(2) p(2) g(2) or 1.08 = 0.5 (0.82) exp [ (0.5) A (0.5) ] + 0.5 (1.93) exp [ (0.5) A (0.5) ]. Then exp [ (0.5) A (0.5) ] = 1.08 / [ 0.5 (0.82 + 1.93) ] = 0.785, A = - 0.97. P for 30 : 70 mixture is P = x(1) p(1) g(1) + x(2) p(2) g(2) = (0.3) (0.82) exp [ (-0.97) (0.7) (0.7) ] + (0.7) (1.93) exp [ (-0.97) (0.3) (0.3) ] = 1.39 bar (proven) where g(1) = exp [ A x(2) x(2) ], g(2) = exp [ A x(1) x(1) ]. The answer is given by Kang Chuen Tat; PO Box 6263, Dandenong, Victoria VIC 3175, Australia; SMS +61405421706; chuentat@hotmail.com; http://kangchuentat.wordpress.com.

MASS TRANSFER - EXAMPLE 4.1 : A concentric, counter-current heat exchanger is used to cool lubricating oil. Water is used as the coolant. The mass flow rate of oil into the heat exchanger is 0.1 kg / s = FO. For oil, the inlet temperature TIO = 100 degree Celsius and the outlet temperature TOO = 55 degree Celsius. For water, the inlet temperature TIW = 35 degree Celsius and the outlet temperature TOW = 42 degree Celsius. What is the mass flow rate of water in kg / s, FW needed to maintain these operating conditions? Constant for heat capacity of oil is CO = 2131 J /(kg K) and for water is CW = 4178 J /(kg K). Use the equation (FO)(CO)(TIO ?TOO) = (FW)(CW)(TOW ?TIW).

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Chemical Engineering Material Balance - Three hundred gallons of a mixture containing 75.0 wt % ethanol and 25 wt % water (mixture specific gravity = 0.877) and a quantity of a 40.0 wt % ethanol - 60 wt % water mixture (specific gravity = 0.952) are blended to produce a mixture containing 60.0 wt % ethanol. The specific gravity of a substance is the ratio of density of a substance compared to the density of water. The symbol of weight percent is wt %. (a) Estimate the specific gravity of the 60 % mixture by assuming that y = mx c where y is wt % ethanol, x is mixture specific gravity. Values for m and c are constants. (b) Determine the required volume of the 40 % mixture.

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