Question 39 - Acetone and ethanol are separated using a distillation column with

Question 39 - Acetone and ethanol are separated using a distillation column with a partial condenser and partial reboiler. An equimolar, sub-cooled liquid feed enters at 100 kmol / hr and condenses 1 mole of vapor for every 6 moles of feed. The separation requires a distillate vapor that is 95 mol % acetone and bottoms liquid that is 5 mol % acetone. The reflux is returned from the condenser to the column as a saturated liquid and the operation is run at (L / V) = 1.4 * (L / V) min. Assume constant overflow conditions. (a) Feed operating line is y = [ q / (q - 1) ] x - z / (q - 1) where z = 0.5 for equimolar liquid mixture of 2 components, q = (L’ - L) / F where L’ = L + F + (F / 6) for condensation of 1 mole of vapor / 6 moles of feed. What is y = f(x)? (b) The rectifying operating line is y = (L / V) x + (D / V) (xd) where (L / V) min goes through the points A (0.95, 0.95) and B (0.53, 0.69), V = L + D. What is y = f(x)? Let xd = 0.95. (L / V) min is the slope of the 2 points A and B.

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Question 39 - Acetone and ethanol are separated using a distillation column with a partial condenser..

Answer / kang chuen tat (malaysia - pen

Answer 39 - (a) q = (F + F / 6) / F = 7 / 6, then y = [ (7 / 6) / (1 / 6) ] x - 0.5 / (1 / 6) or y = 7x - 3. (b) (L / V) min as a slope of AB = (0.95 - 0.69) / (0.95 - 0.53) = 0.62. (L / V) = 1.4 * (L / V) min = 1.4 x 0.62 = 0.868. V = L + D, 1 = (L / V) + (D / V) then (D / V) = 1 - (L / V) = 1 - 0.868 = 0.132, y = 0.868 x + (0.132) (0.95) then y = 0.868 x + 0.1254. The answer is given by Kang Chuen Tat; PO Box 6263, Dandenong, Victoria VIC 3175, Australia; SMS +61405421706; chuentat@hotmail.com; http://kangchuentat.wordpress.com.

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