Answer / yogesh jadhav

m15(1:2:4)
100cum given
wet volume of concrete=30%more than dry volume
=1.3*100=130cum
wastage=20%of wet volume of concrete
=1.2*130=156cum
volume of cement required=156cum/1+2+4=22.28cum
1 bag of cement=35 lit=0.035cum
no of cement bags required=22.28/0.035=636.57=637bags
sand rqd=2*22.28=44.56cum
coarse agg reqd=4*22.28=89.12cum

Answer / sjtbehera

For3 100 cum

Aggregated- 88 cum

Sand-44 cum

Cement- 22cum. 660 bag

Answer / channa

1m3 of dry concrete = 1.54m3 of wet concrete
Concrete work to be done=100×1.54=154m3
Cement=(1/(1+2+4))×154=22m3
Wkt, density of cement=1440kg/m3
Mass of cement=1440×22=31680kg
No of cement bags= 31680/50=634bags of cement required

Answer / vishamvar

For 10cum of M15 (1:2:4)
concrete 15.2cum dry weight
is require thus
for 100cum concrete
approx. Quantity of material
will be

Cement = 21.71 cum
Sand = 43.43 cum
Aggregate = 86.84 cum

Answer / ajit kiling

For 100 cum work
For m15 grade of concrete (1:2:4)
Dry mortar of 1cum =1.54cum For 100cum= 100*1.54
= 154cum
Cement=154/(1+2+4) = 22cum
Sand= 22*2=44cum
Aggregate=22*4=88cum

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