Answer / shivang

cement bags= 23 bags=((1/5.5)*1.57))/0.035
Sand = 1.21 m3= ((1.5/5.5)/1.57))*2.83
Aggregates = 2.42 m3= ((3/5.5)/1.57))*2.83

Answer / single ravi

200*.5=100cft/35.32=2.83cum
2.83*6.5=18.39bags
18.35*50=919.75kg of cement required for the given problem

Answer / md afroz alam

22 bags of cement
42 cft sand
83 cft agg, 20mm size

Answer / guest

Cement bag is 20 Nos
Sand 50 cft
Aggregates 100 cft

As per thumb rule cement required per 1 cum of M20 concrete is 411Kg/cum(1.57/5.5=0.285cum of cement i.e 0.285*1440=411Kg).But as per PWD rate analysis cement required is 347Kg/cum.the difference is 64Kg.This kind of difference is coming every grade of concrete.Can you give perfect suggestion regarding this.

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