Answer / eugene

Viscosity only applies to fluids, ie. gas and liquid.

However, the nature of viscosity for gas and liquid are
different.

In general, the liquid viscosity is dependent on the
strength of intermolecular attraction. The stronger the
intermolecular attraction, the more the viscous the liquid
is.

In fact, raising the temperature of the liquid decreases
its viscosity. This reflects the viscosity of a liquid is
indeed dependent on the intermolecular attraction.

Answer / chem

As we know what is viscosity is
Viscosty is the resistance offered in the motion of fluid.
it is the ratio of the shear stress and velocity gradient
so it depends on the following factors
shear stress
temperature
velocity

Answer / shrinivas prasad bulusuwar

viscosity is basically the resistance to flow, caused by
friction between two adjacent layers of the fluid.
The bottommost layer offers resistance to the adjacent
layer causing decrease in the velocity of the adjacent
layer.
Also, viscosity is caused due to the inter-molecular forces
of attraction.

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ACCOUNTING AND FINANCIAL ENGINEERING - EXAMPLE 34.26 : In a construction accounting for a biochemical processing plant, $A has been spent to date, and another $B is expected required to complete the construction project. The biochemical processing plant is expected to generate a total revenue of $C. Calculate the : (a) estimated total costs; (b) percentage completion of project; (c) total estimated profit; (d) profit to date.

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Question 70 - According to Adolf Eugen Fick (1829 - 1901) : rate of diffusion v increases with less wall thickness t, increased area A and decreased molecular weight of a fluid M. The diffusion constant D decreased with increasing M. (a) By assuming v, t, dP, A, M and D changes proportionally of each other, find the equation of v as a function of t, dP, A and D. (b) The ratio of self diffusion constant D, at T = 273 K and P = 0.1 MPa, for gases B and C are 1.604 : 0.155. If only 2 gases exist in such a system : hydrogen and nitrogen, find the type of gas for B and C with reference to their molecular weights M. (c) By using the equation of kinetic energy 0.5 MV = constant where V = square of v, find the ratio of V for B and V for C, or V(B) / V(C), as a function of M(B) and M(C), where M(B) is molecular weight of B and M(C) the molecular weight of C : Graham's Law of Diffusion.

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