Answer / habeebm

Yes we have formula.....

Power P =400KW, Length L =50 Mtr, Voltage V =415V

ANSWER:-------

First find current,

Current I= 695.65A

Apply the factors in the below mentioned formula:-

R = pL/a

Where R=Resistance, p=Resistivity, L=Length, a=Area

Since p=12 for Aluminiun and 14 for Copper.

Then, R= pL/a

We know that V=IR

Apply "R" in Ohms Law

V = IR

V = I pL/a

Therefore ,

Area "a"= (IpL/V) / 1.732 (since 3 phase)

a = (695.65 x 12 x 50 / 415)/1.732

a = 580.69 ( Approximately 600 Sq.mm )

a = 600 ( 2 x 300 Sq.mm)

Therefore 2R, 3.5C X 300 Sq.mm cable is required.

Answer / noob

wat does 2R mean?
how did u get V = 415v?
50 meters is the length of wat?
the wire? the load?

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