How to calculate the Sizes of the cable required for one
specific load? Is there any formula for that? ( EX: For
400KW load,50mtr Length, What is the LT cable Size
required?)
Answers were Sorted based on User's Feedback
Yes we have formula.....
Power P =400KW, Length L =50 Mtr, Voltage V =415V
ANSWER:-------
First find current,
Current I= 695.65A
Apply the factors in the below mentioned formula:-
R = pL/a
Where R=Resistance, p=Resistivity, L=Length, a=Area
Since p=12 for Aluminiun and 14 for Copper.
Then, R= pL/a
We know that V=IR
Apply "R" in Ohms Law
V = IR
V = I pL/a
Therefore ,
Area "a"= (IpL/V) / 1.732 (since 3 phase)
a = (695.65 x 12 x 50 / 415)/1.732
a = 580.69 ( Approximately 600 Sq.mm )
a = 600 ( 2 x 300 Sq.mm)
Therefore 2R, 3.5C X 300 Sq.mm cable is required.
Is This Answer Correct ? | 7 Yes | 2 No |
Answer / noob
wat does 2R mean?
how did u get V = 415v?
50 meters is the length of wat?
the wire? the load?
Is This Answer Correct ? | 2 Yes | 1 No |
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