what is the cutting length of 90 degree bend in four corner
ring in column of 8mm dia size of column 450mmx250mm of
clear cover 20mm?
Answers were Sorted based on User's Feedback
Answer / sandeep kumar
820+220+(2*80)(i:e we take 2 hook 10d each )-5*16(i:e deduction at five corners of the ring , we take 2d each )=1320
| Is This Answer Correct ? | 19 Yes | 2 No |
Answer / devender singh
Cutting length=2*410+2*210+2*80-5*2*8=1320mm
(10d hook & deduction of 2d on each of five bends)
| Is This Answer Correct ? | 12 Yes | 1 No |
Answer / dhaval
A= 450-2*20-2*8 = 394
B= 250-2*20-2*8 = 194
length = 2*(A+B)+4*6*DIA = 2*(394+194) + 4*6*8= 1368mm
| Is This Answer Correct ? | 2 Yes | 1 No |
Answer / anurag soni
(410+410)+(210+210)+80=1320mm
1320mm cutting length of 8mm bar
| Is This Answer Correct ? | 1 Yes | 0 No |
Answer / abhi
formula 2(A+E)+24d,where A and E are inner to inner
dimension of stirrups i.e A=450-2*20-2*8=384, E=194, so
Lm= 2(384+194)+24*8= 1348mm
| Is This Answer Correct ? | 5 Yes | 5 No |
Answer / ganesan k
410*2+210*2=1240
bend 10*dia,10*8=80*4=240
cutting lenth=1480
| Is This Answer Correct ? | 1 Yes | 1 No |
Answer / rajesh singh
820+420+(2*80)(i:e we take 2 hook 10d each )-5*16(i:e
deduction at five corners of the ring , we take 2d each )=1320
| Is This Answer Correct ? | 0 Yes | 0 No |
Answer / vinay
(450+450+250+250)-8(20){dedudting covers on all 8 sides}+2*10*8{adding hook length 2*10*d}-5*2*8{deducting on all 5 sides 5*2*d}=1320mm
| Is This Answer Correct ? | 0 Yes | 0 No |
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