Answer / sandeep kumar

820+220+(2*80)(i:e we take 2 hook 10d each )-5*16(i:e deduction at five corners of the ring , we take 2d each )=1320

Answer / devender singh

Cutting length=2*410+2*210+2*80-5*2*8=1320mm
(10d hook & deduction of 2d on each of five bends)

Answer / dhaval

A= 450-2*20-2*8 = 394
B= 250-2*20-2*8 = 194
length = 2*(A+B)+4*6*DIA = 2*(394+194) + 4*6*8= 1368mm

Answer / anurag soni

(410+410)+(210+210)+80=1320mm
1320mm cutting length of 8mm bar

Answer / abhi

formula 2(A+E)+24d,where A and E are inner to inner
dimension of stirrups i.e A=450-2*20-2*8=384, E=194, so
Lm= 2(384+194)+24*8= 1348mm

Answer / ganesan k

410*2+210*2=1240
bend 10*dia,10*8=80*4=240
cutting lenth=1480

Answer / muthaa

1400 mm

Answer / rajesh singh

820+420+(2*80)(i:e we take 2 hook 10d each )-5*16(i:e
deduction at five corners of the ring , we take 2d each )=1320

Answer / vinay

(450+450+250+250)-8(20){dedudting covers on all 8 sides}+2*10*8{adding hook length 2*10*d}-5*2*8{deducting on all 5 sides 5*2*d}=1320mm

Answer / mahesh_pandey05

1256 mm

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