if the voltage across the lamp drops by 1%, the power drawn will be reduced by

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if the voltage across the lamp drops by 1%, the power drawn
will be reduced by how many %?

Question Posted / kabindra

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if the voltage across the lamp drops by 1%, the power drawn will be reduced by how many %?..

Answer / eee

Power = V(square)/R

If voltage is reduced by 1% power will drop by
.99*.99 = .9801

(1-0.9801)*100

Power is reduced by 1.99%.

Is This Answer Correct ?

58 Yes

11 No

if the voltage across the lamp drops by 1%, the power drawn will be reduced by how many %?..

Answer / nirmal maity

Let, voltage across the lamp =100v and resistance R =100 ohm
so, power P =v*I = 100*1=100W {I =V/R =100/100=1 }
If the voltage across the lamp drops by 1 percentage , then present voltage is 99v
Then present power drown by the lamp whose resistance R =100 ohm is P =V^2/R = 98*98/100 = 98.01W .
So power drop of the lamp is 100-98 =2 w

so the power drawn will be reduced by 2percentage

Is This Answer Correct ?

29 Yes

9 No

if the voltage across the lamp drops by 1%, the power drawn will be reduced by how many %?..

Answer / wareagle

Watts = E x I
I = E/R
W = E x E/R = .99E x .99E/R = 0.98 watts

Is This Answer Correct ?

10 Yes

9 No

if the voltage across the lamp drops by 1%, the power drawn will be reduced by how many %?..

Answer / k.prakashchandra

If you connect phase and neutral across the bulb the voltage
should fully drop.1% drop is possible if there are 99
similar bulbs in series with it or a resistance of 99 times
the bulb resistance.

Is This Answer Correct ?

1 Yes

10 No

if the voltage across the lamp drops by 1%, the power drawn will be reduced by how many %?..

Answer / brijesh soni

if you will conect the lamp drop by 1% the power drown by
the bulb will be 1%

Is This Answer Correct ?

2 Yes

17 No

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