Answer / surajit ghosh

LBD= 24 X 43 X 0.125 (SAY, REQUIRED TO ACHIEVE AS PER
DESIGN)= 129 CUM
VOLUME OF STEEL 1% (SAY, REQUIRED TO ACHIEVE AS PER DESIGN
& BBS)= 1.29 CUM= 1.29X 7850 kG= 10126 kG, Apx= 10 Ton.

Answer / arsh

No. of bars*Total Length*(Dia of bar)^2*(1/162)
The answer will be in kgs.

Answer / ronak shah

generally it is depending upon the design of slab, becasue
you have such big sapn so there is beam between them. its
depends upon how to design the slab by structral engineer.
generally its depends upon client rquirement.

Answer / ashok kumar chaudhary

Dear Sir,

SOLUTION :-

Length of Slab = 43M
Width of Slab = 24M
Heigth of Slab = -----(Not Given)

You can not find the quantity of reinforcement .

Answer / saravanan

hi.
1) length of slab/spacing=no of bar lager side
2) width of slab/spacing=no of bars in shorter side
3) length of one bar = length of slab-(2*cover thickens)
4) length of one bar longer side*total no of bars in longer side(+)length of one bar shorter side*total no of bars=total length of bars requirement in slab
..weight of one meter bar =d^2/162
total weight of bars=total length of bar*weight of bar

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