Answer / bashar khawaldeh

int arr[8];
int sum = 0;
int n = sizeof(arr) / sizeof(arr[0]);//24/4=6
for (int i = 0; i < n; i++) {
cout << "enter binary number
" << "index " << i << ":";
cin >> arr[i];
}

for (int i = 0; i < n; i++) {

if (arr[i] == 1) {
sum += pow(2,i);
}
}
cout << sum << endl;

void main() { int i=5,y=3,z=2,ans; clrscr(); printf("%d",++i + --z + i++ + --i * ++y); i=5,y=3,z=2; ans=++i + --z + i++ + --i * ++y; printf("\n%d",ans); getch(); } Its output is 37 and 31.... Please explain me why its different How it works.....

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