char *someFun()
{
char *temp = “string constant";
return temp;
}
int main()
{
puts(someFun());
}
Answer / susie
Answer :
string constant
Explanation:
The program suffers no problem and gives the output
correctly because the character constants are stored in
code/data area and not allocated in stack, so this doesn’t
lead to dangling pointers.
| Is This Answer Correct ? | 4 Yes | 0 No |
String copy logic in one line.
main() { extern int i; i=20; printf("%d",sizeof(i)); }
#define FALSE -1 #define TRUE 1 #define NULL 0 main() { if(NULL) puts("NULL"); else if(FALSE) puts("TRUE"); else puts("FALSE"); }
void main() { static int i=5; if(--i){ main(); printf("%d ",i); } }
There is a lucky draw held every day. if there is a winning number eg 1876,then all possible numbers like 1867,1687,1768 etc are the numbers that match irrespective of the position of the digit. Thus all these numbers qualify fr the lucky draw prize Assume there is no zero digit in any numbers. write a program to show all the possible winning numbers if a "winning number"is passed as an arguments to the function.
#include<stdio.h> main() { int a[2][2][2] = { {10,2,3,4}, {5,6,7,8} }; int *p,*q; p=&a[2][2][2]; *q=***a; printf("%d..%d",*p,*q); }
x=2 y=3 z=2 x++ + y++; printf("%d%d" x,y);
#if something == 0 int some=0; #endif main() { int thing = 0; printf("%d %d\n", some ,thing); }
struct point { int x; int y; }; struct point origin,*pp; main() { pp=&origin; printf("origin is(%d%d)\n",(*pp).x,(*pp).y); printf("origin is (%d%d)\n",pp->x,pp->y); }
main() { signed int bit=512, mBit; { mBit = ~bit; bit = bit & ~bit ; printf("%d %d", bit, mBit); } } a. 0, 0 b. 0, 513 c. 512, 0 d. 0, -513
3 Answers HCL, Logical Computers,
#include<stdio.h> main() { char s[]={'a','b','c','\n','c','\0'}; char *p,*str,*str1; p=&s[3]; str=p; str1=s; printf("%d",++*p + ++*str1-32); }
main() { char a[4]="HELLO"; printf("%s",a); }