Answer / susie

Answer :

string constant

Explanation:

The program suffers no problem and gives the output
correctly because the character constants are stored in
code/data area and not allocated in stack, so this doesn’t
lead to dangling pointers.

Given only putchar (no sprintf, itoa, etc.) write a routine putlong that prints out an unsigned long in decimal.

6 Answers   Fusion Systems GmbH,

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main() { clrscr(); } clrscr();

2 Answers  

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main() { if (!(1&&0)) { printf("OK I am done."); } else { printf("OK I am gone."); } } a. OK I am done b. OK I am gone c. compile error d. none of the above

3 Answers   HCL,

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how to print 1 2 3 4 5 6 7 8 9 10 9 8 7 6 5 4 3 2 1 using any loop(for or while) only once(only 1 loop) and maximum 2 variables using C.

19 Answers   Cap Gemini, Infosys,

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/*what is the output for*/ void main() { int r; printf("Naveen"); r=printf(); getch(); }

4 Answers  

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main() { void swap(); int x=10,y=8; swap(&x,&y); printf("x=%d y=%d",x,y); } void swap(int *a, int *b) { *a ^= *b, *b ^= *a, *a ^= *b; }

2 Answers  

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Is this code legal? int *ptr; ptr = (int *) 0x400;

1 Answers  

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#define a 10 void foo() { #undef a #define a 50 } int main() { printf("%d..",a); foo(); printf("%d..",a); return 0; } explain the answer

1 Answers  

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#define FALSE -1 #define TRUE 1 #define NULL 0 main() { if(NULL) puts("NULL"); else if(FALSE) puts("TRUE"); else puts("FALSE"); }

1 Answers  

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main() { int i=300; char *ptr = &i; *++ptr=2; printf("%d",i); }

4 Answers   CSC,

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print numbers till we want without using loops or condition statements like specifically(for,do while, while swiches, if etc)!

11 Answers   Wipro,

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void main() { int i=5; printf("%d",i++ + ++i); }

3 Answers  

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