main( )
{
int a[2][3][2] = {{{2,4},{7,8},{3,4}},{{2,2},{2,3},{3,4}}};
printf(“%u %u %u %d \n”,a,*a,**a,***a);
printf(“%u %u %u %d \n”,a+1,*a+1,**a+1,***a+1);
}
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Answer / susie
Answer :
100, 100, 100, 2
114, 104, 102, 3
Explanation:
The given array is a 3-D one. It can also be viewed as a
1-D array.
2
4
7
8
3
4
2
2
2
3
3
4
100 102 104 106 108 110 112 114 116 118
120 122
thus, for the first printf statement a, *a, **a give
address of first element . since the indirection ***a gives
the value. Hence, the first line of the output.
for the second printf a+1 increases in the third dimension
thus points to value at 114, *a+1 increments in second
dimension thus points to 104, **a +1 increments the first
dimension thus points to 102 and ***a+1 first gets the value
at first location and then increments it by 1. Hence, the
output.
| Is This Answer Correct ? | 11 Yes | 17 No |
main() { int a[10]; printf("%d",*a+1-*a+3); }
programming in c lanugaue programm will errror error with two header file one as stdio.h and other one is conio.h
main() { extern i; printf("%d\n",i); { int i=20; printf("%d\n",i); } }
#include<stdio.h> main() { int a[2][2][2] = { {10,2,3,4}, {5,6,7,8} }; int *p,*q; p=&a[2][2][2]; *q=***a; printf("%d----%d",*p,*q); }
Link list in reverse order.
What is the output of the program given below main() { signed char i=0; for(;i>=0;i++) ; printf("%d\n",i); }
union u { struct st { int i : 4; int j : 4; int k : 4; int l; }st; int i; }u; main() { u.i = 100; printf("%d, %d, %d",u.i, u.st.i, u.st.l); } a. 4, 4, 0 b. 0, 0, 0 c. 100, 4, 0 d. 40, 4, 0
main() { int i=5,j=6,z; printf("%d",i+++j); }
Which one is taking more time and why ? :/home/amaresh/Testing# cat time.c //#include <stdio.h> #define EOF -1 int main() { register int c; while ((c = getchar()) != EOF) { putchar(c); } return 0; } ------------------- WIth stdio.h:- :/home/amaresh/Testing# time ./time_header hi hi hru? hru? real 0 m4.202s user 0 m0.000s sys 0 m0.004s ------------------ Witout stdio.h and with #define EOF -1 =================== /home/amaresh/Testing# time ./time_EOF hi hi hru? hru? real 0 m4.805s user 0 m0.004s sys 0 m0.004s -- From above two case , why 2nd case is taking more time ?
main() { signed int bit=512, i=5; for(;i;i--) { printf("%d\n", bit >> (i - (i -1))); } } a. 512, 256, 0, 0, 0 b. 256, 256, 0, 0, 0 c. 512, 512, 512, 512, 512 d. 256, 256, 256, 256, 256
main() { printf("\nab"); printf("\bsi"); printf("\rha"); }
void main() { static int i=i++, j=j++, k=k++; printf(“i = %d j = %d k = %d”, i, j, k); }